Node existingUserNode = loginDoc.selectSingleNode("/returningUser");
String username = existingUserNode.selectSingleNode("/username").getText();
String password = existingUserNode.selectSingleNode("/password").getText();为
<?xml version="1.0" encoding="UTF-8"?><returningUser><username>user</username><password>password</password></returningUser>返回null。
我不认为我的xpath是错误的?或者我使用了错误的方法?
发布于 2010-08-10 05:19:42
语法应该是./username和./password...在上面,通过引用根,我看起来太高了一层
发布于 2010-08-10 05:21:33
尝尝这个
Node existingUserNode = loginDoc.selectSingleNode("/returningUser");
String username = existingUserNode.selectSingleNode("/username").getNodeValue();
String password = existingUserNode.selectSingleNode("/password").getNodeValue();https://stackoverflow.com/questions/3444263
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