尊重,
我尝试使用新的Java在客户端和服务器端创建异步SocketChannel并进行通信,但问题是我发送到socket的所有消息都在服务器上,socket读取所有消息作为一条消息。下面是代码:
我创建用于写入和读取数据的处理程序:
ReadHandler:
public class ReadHandler implements CompletionHandler<Integer, Msg> {
private AsynchronousSocketChannel _socket;
private SocketHandler _socketHandler;
private ByteBuffer _buffer;
public ReadHandler(SocketHandler socketHandler) {
this._socketHandler = socketHandler;
_buffer = ByteBuffer.allocate(100);
this._socket = this._socketHandler.getSocket();
this._socket.read(_buffer, null, this);
}
@Override
public void completed(Integer result, Msg attachment) {
System.out.println("readdddd " + result);
String message = new String(_buffer.array());
System.out.println("mess:" + message);
}
@Override
public void failed(Throwable exc, Msg attachment) {
System.out.println(exc.getMessage());
}}
ClientWriteHandler
public class ClientWriteHandler implements CompletionHandler<Integer, Msg> {
private AsynchronousSocketChannel _socket;
private ClientSocket _clientHandler;
private ByteBuffer _buffer;
public ClientWriteHandler(ClientSocket clientHandler) {
this._clientHandler = clientHandler;
_buffer = ByteBuffer.allocate(2048);
this._socket = this._clientHandler.getSocket();
}
@Override
public void completed(Integer result, Msg attachment) {
System.out.println("write " + result);
_buffer.clear();
}
@Override
public void failed(Throwable exc, Msg attachment) {
System.out.println(exc.getMessage());
}
public void write(String data) {
_buffer = ByteBuffer.allocate(2048);
this._socket.write(_buffer.wrap(data.getBytes()), new Msg(), this);
}}
然后我调用write方法2次
socket = AsynchronousSocketChannel.open();
socket.connect(new InetSocketAddress("localhost", port)).get();
writeHandler = new ClientWriteHandler(this);
writeHandler.write("hellooo server :)");
writeHandler.write("hellooo server again :)");我尝试在ByteBuffer上使用clear()函数,但没有效果。有什么建议吗?
发布于 2014-09-11 21:03:16
引发WritePendingException不是因为缓冲区已满。它被抛出是因为写入未完成,但另一个开始写入。
发布于 2014-04-24 21:34:47
在第一个.write()调用中发送了几个字节,在第二个.write()调用中发送了几个字节。并且服务器接收所有它们。TCP是面向字节的。如果你想要消息之类的东西,你必须自己分隔你发送的消息,例如用特殊的换行符或XML标签。
发布于 2014-04-25 04:46:40
我在这上面工作,我找到了解决方案,就像我想象的那样。
在ClientWrite处理程序中,我添加了数据列表,并在try..catch中设置了write方法,以检查write()是否已完成,如果写入仍在进行中,则将新字符串添加到数据列表中。当write方法完成时,我检查数据列表中是否有新的消息,并再次写入消息。
public class ClientWriteHandler implements CompletionHandler<Integer, ByteBuffer> {
private AsynchronousSocketChannel _socket;
private ClientSocket _clientHandler;
private ByteBuffer _buffer;
private List<String> datas;
private boolean finished;
public ClientWriteHandler(ClientSocket clientHandler) {
this._clientHandler = clientHandler;
_buffer = ByteBuffer.allocate(2048);
this._socket = this._clientHandler.getSocket();
finished = true;
datas = new ArrayList<>();
}
@Override
public void completed(Integer result, ByteBuffer attachment) {
System.out.println("client write complete " + result);
if(datas.size() > 0) {
this._socket.write(_buffer.wrap(datas.remove(0).getBytes()), _buffer, this);
}
else {
/////
}
}
@Override
public void failed(Throwable exc, ByteBuffer attachment) {
System.out.println(exc.getMessage());
}
public void write(String data) {
try {
//finished = false;
this._socket.write(_buffer.wrap(data.getBytes()), _buffer, this);
}catch(WritePendingException ex) {
datas.add(data);
}
}}
此外,我在附件中发送缓冲区。在ReadHandler中,当读取完成时,我清除ByteBuffer并再次调用read()方法,所以下一次读取时,我得到了新的行,现在我不需要设置行分隔符。
public class ReadHandler implements CompletionHandler<Integer, ByteBuffer> {
private AsynchronousSocketChannel _socket;
private SocketHandler _socketHandler;
private ByteBuffer _buffer;
public ReadHandler(SocketHandler socketHandler) {
this._socketHandler = socketHandler;
_buffer = ByteBuffer.allocate(2048);
this._socket = this._socketHandler.getSocket();
this._socket.read(_buffer, _buffer, this);
}
@Override
public void completed(Integer result, ByteBuffer attachment) {
attachment.flip();
System.out.println("readdddd " + result);
String message = new String(attachment.array());
System.out.println("mess:" + message);
_buffer.clear();
this._socket.read(_buffer, _buffer, this);
}
@Override
public void failed(Throwable exc, ByteBuffer attachment) {
System.out.println(exc.getMessage());
}}
就目前而言,这很好用,但我将检查当我继续处理更复杂的东西时,这段代码将如何运行。你觉得这个解决方案可以吗?
https://stackoverflow.com/questions/23270240
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