问如何计算字符串的grep结果，但指定排除项？

EN

awk -F= '$2 != "127.0.0.1"  &&  /relay/ {count[$2]++; total++} 
  END { print "total relay = "total; 
        for (k in count) { print k" = " count[k]}
      }' maillog

 grep relay maillog  | cut -d= -f2 | grep -v 127.0.0.1 | uniq -c

perl -ne '/relay=(.*)/ and $1 ne "127.0.0.1" and ++$t and $h{$1}++;
  END {print "total = $t\n"; 
       print "$_ = $h{$_}\n" foreach keys %h;
  }' maillog

 awk -F= '$2!="127.0.0.1"&&$2{t++;a[$2]++} END{print "total relay="t; for(x in a)print x"="a[x]}' yourfile

total relay=6
mx2.xyz.com=1
mx1.xyz.com=2
mx3.xyz.com=2
home.xyz.abc.com=1

cut -d= -f2 filename | grep -v -e '^[[:space:]]*$' -e 127.0.0.1 | sort | uniq -c | tee >(echo "$(bc <<< $(sed -e 's#[[:alpha:]].\+$#+#' -e '$a0')) total") | sed 's/^ *\([0-9]\+\) \(.*\)/\2 = \1/' | tac

total = 6
mx3.xyz.com = 2
mx2.xyz.com = 1
mx1.xyz.com = 2
home.xyz.abc.com = 1