我尝试用dropzone.js上传文件。我的问题是,我在一个页面上有四个dropzone上传容器,用于不同的图像。如何将选定的div发布到post事件?
<div class='product_thumbs'>
<form name="product_image_1" action="ajax/upload.php" class="dropzone">
<div class="product_image image_1" id="image_1">
<div class="fallback">
<i class="fa fa-upload"></i>
<input id="file_1" type="file" multiple />
</div>
</div>
<div class="product_image image_2" id="image_2">
<div class="fallback">
<i class="fa fa-upload"></i>
<input id="file_2" type="file" multiple />
</div>
</div>
<div class="product_image image_3" id="image_3">
<div class="fallback">
<i class="fa fa-upload"></i>
<input id="file_3" type="file" multiple />
</div>
</div>
<div class="product_image image_4" id="image_4">
<div class="fallback">
<i class="fa fa-upload"></i>
<input id="file_4" type="file" multiple />
</div>
</div>
</form>
</div>$(document).ready(function() {
$(".image_1, .image_2, .image_3, .image_4").dropzone({
url: "ajax/upload.php?product_id=" + $("#product_id").val() + "&image_number=" + $(this.element).data("id"), // Here I´ll post the id
thumbnailWidth: 100,
thumbnailHeight: 120,
addRemoveLinks: false,
previewTemplate: ""+
"<div class=\"dz-preview dz-file-preview\">"+
"<div class=\"dz-details\">"+
//"<div class=\"dz-filename\"><span data-dz-name></span></div>"+
//"<div class=\"dz-size\" data-dz-size></div>"+
"<img data-dz-thumbnail />"+
"</div>"+
"<div class=\"dz-progress\"><span class=\"dz-upload\" data-dz-uploadprogress></span></div>"+
"<div class=\"dz-error-message\"><span data-dz-errormessage></span></div>"+
"</div>"
});
});添加图片后如何编辑URL?我还将发布所选文件容器的类或id……
发布于 2014-11-17 22:10:54
试试这个:
$(this).attr("id")获取当前div的id
发布于 2014-11-17 22:39:21
我不知道你想要达到什么目的。
如果你想简单地发布所有的输入文件,给它们起一个相同的名字,例如name="file[]",[]表示它是一个数组。
https://stackoverflow.com/questions/26974250
复制相似问题