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问挑选一张照片或拍摄一张照片，并使用onActivityResult()来处理两者都不起作用的情况
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Stack Overflow用户

提问于 2015-07-10 17:49:11

回答 2查看 1.7K关注 0票数 0

我正在尝试创建一个应用程序，因为我既可以拍摄新照片，也可以使用现有的照片。我让这两个函数单独工作，但不能一起工作。当Uri imageUri = data.getData();运行时，应用程序崩溃。

代码如下：

 public void btnPhotoClicked(View v) {

    //Use to invoke a Camera
    Intent cameraIntent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
    //Create a variable with the filepath generated by the android operating system, Like a baws

    File pictureDirectory = Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_DCIM);
    if (pictureDirectory.exists()) {
        File test1 = new File(pictureDirectory, "100MEDIA/");
        if (test1.exists()) {
            pictureDirectory = test1;
        } else {
            File test2 = new File(pictureDirectory, "100ANDRO/");
            if (test2.exists()) {
                pictureDirectory = test2;
            } else {
                File test3 = new File(pictureDirectory, "Camera/");
                if (!test3.exists()) {
                    test3.mkdirs();
                }
                pictureDirectory = test3;
            }
        }
    } else {
        pictureDirectory = new File(pictureDirectory, "Camera/");
        pictureDirectory.mkdirs();
    }

    String pictureName = getPictureName();
    File imageFile = new File(pictureDirectory, pictureName);
    Uri pictureUri = Uri.fromFile(imageFile);
    cameraIntent.putExtra(MediaStore.EXTRA_OUTPUT, pictureUri);


    //Start intent and anticipate result
    startActivityForResult(cameraIntent, CAMERA_RESULT);
}

下面是protected void onActivityResult(int requestCode, int resultCode, Intent data)的代码

protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);

if (resultCode == RESULT_OK) {
    //if we are here everything processed successfully

    if (requestCode==IMAGE_GALLERY_REQUEST) {
        //If we are here we came from the Välj existerande build
        Log.d("MainActivity", data.toString());
        Toast.makeText(this, "IMAGE GALLERY_REQUEST", Toast.LENGTH_LONG).show();
        //the address of the image on the device SD-card
        Uri imageUri = data.getData();

        //Declare a stream to read the image data from the SD-card
        InputStream inputStream;

        //Getting a Input stream based upon the image uri
        try {
            //if it execute flawlessly
            inputStream = getContentResolver().openInputStream(imageUri);

            Bitmap image = BitmapFactory.decodeStream(inputStream);

            //show the image to the user

            mImageView.setImageBitmap(image);

        } catch (FileNotFoundException e) {
            //show massage saying if the image is unavailable
            Toast.makeText(this, "Could not open image", Toast.LENGTH_LONG).show();
        }

    } else if (requestCode == CAMERA_RESULT) {
        //We are here because we have received a result from the camera
        Toast.makeText(this, "CAMERA RESULT", Toast.LENGTH_LONG).show();
        Log.d("MainActivity", data.toString());
        //the address of the image on the device SD-card
        Uri imageUri = data.getData();

        //Declare a stream to read the image data from the SD-card
        InputStream inputStream;

        //Getting a Input stream based upon the image uri
        try {
            //if it execute flawlessly
            inputStream = getContentResolver().openInputStream(imageUri);

            Bitmap image = BitmapFactory.decodeStream(inputStream);
            //show the image to the user

            mImageView.setImageBitmap(image);

        } catch (FileNotFoundException e) {
            //show massage saying if the image is unavailable
            Toast.makeText(this, "Could not open image", Toast.LENGTH_LONG).show();
        }



    }

}

android

android-intent

android-camera

回答 2

Stack Overflow用户

发布于 2015-07-10 19:12:47

尝试使用此选项代替图像uri

if (resultCode == RESULT_OK)
        {
            if (requestCode == 1) 
            {
                File f = new File(Environment.getExternalStorageDirectory().toString());
                for (File temp : f.listFiles()) 
                {
                  if (temp.getName().equals(tempFile)) 
                  {
                        f = temp;
                        //File photo = new File(Environment.getExternalStorageDirectory(), tempFile);
                        break;
                    }
                }
                try
                {
                    Bitmap bitmap;
                    BitmapFactory.Options bitmapOptions = new BitmapFactory.Options();
                    bitmap = BitmapFactory.decodeFile(f.getAbsolutePath(),bitmapOptions); 
                    final int THUMBNAIL_SIZE = 100;
                    bitmap = Bitmap.createScaledBitmap(bitmap,THUMBNAIL_SIZE, THUMBNAIL_SIZE, false);

                    img.setImageBitmap(bitmap);

                    String path = android.os.Environment.getExternalStorageDirectory()+ File.separator;

                    File file = new File(path,tempFile);

                    updPath=file.toString();
                    imgSel = true;
                    success=true;
                }
                catch (Exception e) 
                {
                    Toast.makeText(this, e.toString(), Toast.LENGTH_LONG).show();
                }
            } 
            else if (requestCode == 2) 
            {
                try
                {
                    Uri selectedImage = data.getData();
                    String[] filePath = { MediaColumns.DATA };
                    Cursor c = getContentResolver().query(selectedImage,filePath, null, null, null);
                    c.moveToFirst();
                    int columnIndex = c.getColumnIndex(filePath[0]);
                    String picturePath = c.getString(columnIndex);
                    c.close();
                    File outputPath= new File(android.os.Environment.getExternalStorageDirectory(), tempFile);
                    updPath = outputPath.toString();
                    copyFile(picturePath, updPath);

                    Bitmap thumbnail = (BitmapFactory.decodeFile(updPath));
                    final int THUMBNAIL_SIZE = 100;
                    thumbnail = Bitmap.createScaledBitmap(thumbnail,THUMBNAIL_SIZE, THUMBNAIL_SIZE, false);
                    ByteArrayOutputStream bytearroutstream = new ByteArrayOutputStream(); 
                    thumbnail.compress(Bitmap.CompressFormat.JPEG, 100,bytearroutstream);
                    img.setImageBitmap(thumbnail);
                    imgSel = true;
                    success=true;
                }
                catch (Exception e) 
                {
                    Toast.makeText(this, e.toString(), Toast.LENGTH_LONG).show();
                }
            }
        }

票数 0

Stack Overflow用户

发布于 2015-07-10 19:35:07

默认的Android相机应用程序仅在返回的Intent中传回缩略图时才返回非空intent。如果您传递带有要写入的URI的EXTRA_OUTPUT，它将返回一个null意图，图片位于您传入的URI中。

你可以通过查看GitHub上相机应用的源代码来验证这一点：

https://github.com/android/platform_packages_apps_camera/blob/gingerbread-release/src/com/android/camera/Camera.java#L1186

你的应用程序就会崩溃。因为getContentResolver().openInputStream(imageUri)调用空对象的方法。imageUri为空。

来自documentation

公共静态最终字符串EXTRA_OUTPUT

在API级别3中添加

Intent-extra的名称，用于指示要用于存储请求的图像或视频的内容解析器Uri。

常量值："output“

所以，你调用ACTION_IMAGE_CAPTURE intent，你应该像这样传递额外的：

Intent photo = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
Uri uri  = Uri.parse("file:///sdcard/photo.jpg");
photo.putExtra(android.provider.MediaStore.EXTRA_OUTPUT, uri);
startActivityForResult(takePicture,requestCode);

然后在onActivityResult中

if (requestCode == CAMERA_REQUEST_CODE) {
        if (resultCode == Activity.RESULT_OK) {
            File file = new File(Environment.getExternalStorageDirectory().getPath(), "photo.jpg");
            Uri uri = Uri.fromFile(file);
            Bitmap bitmap;
            try {
                bitmap = MediaStore.Images.Media.getBitmap(getContentResolver(), uri);
                bitmap = crupAndScale(bitmap, 300); // if you mind scaling
                pofileImageView.setImageBitmap(bitmap);
            } catch (FileNotFoundException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }

        }
    }

已更新

票数 0

页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持

原文链接：

https://stackoverflow.com/questions/31337724

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