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社区首页 >问答首页 >onKeyDown和onKeyLongPress

问onKeyDown和onKeyLongPress
EN

Stack Overflow用户
提问于 2012-10-18 16:26:21
回答 4查看 40.6K关注 0票数 10

我希望我的应用程序对音量按钮的正常按键事件和长按按键事件有不同的反应。

我已经看过this了，但是如果我一直按住音量按钮，在我得到KeyLongPressed事件之前，我会得到很多KeyDown事件。

我希望有一个或另一个事件，而不是两者都有，这样我就可以在短按下调整音量，在长按下跳过音轨。

你能帮帮我吗？

这是我的代码：

代码语言：javascript
复制
    @Override
public boolean onKeyLongPress(int keyCode, KeyEvent event) {
    if (keyCode == KeyEvent.KEYCODE_VOLUME_DOWN) 
    {
        Log.d("Test", "Long press!");
        return true;
    }
    return super.onKeyLongPress(keyCode, event);
}

@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
    if (keyCode == KeyEvent.KEYCODE_VOLUME_DOWN) {
        event.startTracking();
        Log.d("Test", "Short");
        return true;
    }

    return super.onKeyDown(keyCode, event);
}

感谢任何帮助！-爱瑞丝

android
keylistener
EN

回答 4

Stack Overflow用户

回答已采纳

发布于 2012-10-18 17:05:07

这是我写的代码。它就像一种护身符。也许你可以对它进行优化，以获得更好的逻辑。但你会得到它的要点。关键是使用标志。Short press是一种按下音量键并释放的按键。因此，onKeyUp将帮助我们检测短按压。

代码语言：javascript
复制
package com.example.demo;

import android.app.Activity;
import android.os.Bundle;
import android.util.Log;
import android.view.KeyEvent;
import android.view.Menu;

public class TestVolumeActivity extends Activity {
    boolean flag = false;

    boolean flag2 = false;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_splash_screen);
    }

    @Override
    public boolean onCreateOptionsMenu(Menu menu) {
        getMenuInflater().inflate(R.menu.activity_splash_screen, menu);
        return true;
    }

    @Override
    public boolean onKeyLongPress(int keyCode, KeyEvent event) {
        if (keyCode == KeyEvent.KEYCODE_VOLUME_DOWN) {
            Log.d("Test", "Long press!");
            flag = false;
            flag2 = true;
            return true;
        }
        return super.onKeyLongPress(keyCode, event);
    }

    @Override
    public boolean onKeyDown(int keyCode, KeyEvent event) {
        if (keyCode == KeyEvent.KEYCODE_VOLUME_DOWN) {
            event.startTracking();
            if (flag2 == true) {
                flag = false;
            } else {
                flag = true;
                flag2 = false;
            }

            return true;
        }
        return super.onKeyDown(keyCode, event);
    }

    @Override
    public boolean onKeyUp(int keyCode, KeyEvent event) {
        if (keyCode == KeyEvent.KEYCODE_VOLUME_DOWN) {

            event.startTracking();
            if (flag) {
                Log.d("Test", "Short");
            }
            flag = true;
            flag2 = false;
            return true;
        }

        return super.onKeyUp(keyCode, event);
    }
}

所有长按的日志(未检测到短按)：

代码语言：javascript
复制
10-18 02:06:15.369: D/Test(16834): Long press!
10-18 02:06:18.683: D/Test(16834): Long press!
10-18 02:06:21.566: D/Test(16834): Long press!
10-18 02:06:23.738: D/Test(16834): Long press!

适用于所有短印刷机的日志：

代码语言：javascript
复制
10-18 02:07:42.422: D/Test(16834): Short
10-18 02:07:43.203: D/Test(16834): Short
10-18 02:07:43.663: D/Test(16834): Short
10-18 02:07:44.144: D/Test(16834): Short
票数 15
EN

Stack Overflow用户

发布于 2013-09-14 15:30:44

根据SDK正确处理长按键的方式。

代码语言：javascript
复制
import android.app.Activity;
import android.util.Log;
import android.view.KeyEvent;


public class TestVolumeActivity extends Activity
{
    private static final String TAG = TestVolumeActivity.class.getSimpleName();

    @Override
    public boolean onKeyDown(int keyCode, KeyEvent event) {
        if( keyCode == KeyEvent.KEYCODE_VOLUME_UP || 
            keyCode == KeyEvent.KEYCODE_VOLUME_DOWN)
        {
            event.startTracking();
            return true;
        }
        return super.onKeyDown(keyCode, event);
    }

    @Override
    public boolean onKeyLongPress(int keyCode, KeyEvent event)
    {
        if(keyCode == KeyEvent.KEYCODE_VOLUME_UP){
            Log.d(TAG, "Long press KEYCODE_VOLUME_UP");
            return true;
        }
        else if(keyCode == KeyEvent.KEYCODE_VOLUME_DOWN){
            Log.d(TAG, "Long press KEYCODE_VOLUME_DOWN");
            return true;
        }
        return super.onKeyLongPress(keyCode, event);
    }

    @Override
    public boolean onKeyUp(int keyCode, KeyEvent event)
    {
        if((event.getFlags() & KeyEvent.FLAG_CANCELED_LONG_PRESS) == 0){
            if(keyCode == KeyEvent.KEYCODE_VOLUME_UP){
                Log.e(TAG, "Short press KEYCODE_VOLUME_UP");
                return true;
            }
            else if(keyCode == KeyEvent.KEYCODE_VOLUME_DOWN){
                Log.e(TAG, "Short press KEYCODE_VOLUME_DOWN");
                return true;
            }
        }
        return super.onKeyUp(keyCode, event);
    }
}
票数 8
EN

Stack Overflow用户

发布于 2012-10-18 17:20:34

当我正要发布我的答案时，我发现有人已经得到了某种解决方案……

但这里是我的，简单，工作起来像一个魔法师。只有一面旗帜;)

此代码检测短按和长按，当长按发生时，不会触发短按！

注意：如果您想要正常的音量升降行为，请将onKeyPress方法中的返回true更改为超级调用，如下所示：

代码语言：javascript
复制
event.startTracking();
if(event.getRepeatCount() == 0){
    shortPress = true;
}
//return true;
return super.onKeyDown(keyCode, event);

没有超级调用的代码：

代码语言：javascript
复制
private boolean shortPress = false;

@Override
public boolean onKeyLongPress(int keyCode, KeyEvent event) {
    if (keyCode == KeyEvent.KEYCODE_VOLUME_DOWN) {
        shortPress = false;
        Toast.makeText(this, "longPress", Toast.LENGTH_LONG).show();
        return true;
    }
    //Just return false because the super call does always the same (returning false)
    return false;
}

@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
    if (keyCode == KeyEvent.KEYCODE_VOLUME_DOWN) {
        if(event.getAction() == KeyEvent.ACTION_DOWN){
            event.startTracking();
            if(event.getRepeatCount() == 0){
                shortPress = true;
            }
            return true;
        }
    }
    return super.onKeyDown(keyCode, event);
}

@Override
public boolean onKeyUp(int keyCode, KeyEvent event) {
    if (keyCode == KeyEvent.KEYCODE_VOLUME_DOWN) {
        if(shortPress){
            Toast.makeText(this, "shortPress", Toast.LENGTH_LONG).show();
        } else {
            //Don't handle longpress here, because the user will have to get his finger back up first
        }
        shortPress = false;
        return true;
    }
    return super.onKeyUp(keyCode, event);
}

下面的代码添加了音量调高键，只需选择您所在的位置;)

代码语言：javascript
复制
private boolean shortPress = false;

@Override
public boolean onKeyLongPress(int keyCode, KeyEvent event) {
    if (keyCode == KeyEvent.KEYCODE_VOLUME_DOWN) {
        shortPress = false;
        Toast.makeText(this, "longPress Volume Down", Toast.LENGTH_LONG).show();
        return true;
    } else if(keyCode == KeyEvent.KEYCODE_VOLUME_UP){
        shortPress = false;
        Toast.makeText(this, "longPress Volume Up", Toast.LENGTH_LONG).show();
        return true;
    }
    //Just return false because the super call does always the same (returning false)
    return false;
}

@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
    if (keyCode == KeyEvent.KEYCODE_VOLUME_DOWN || keyCode == KeyEvent.KEYCODE_VOLUME_UP) {
        if(event.getAction() == KeyEvent.ACTION_DOWN){
            event.startTracking();
            if(event.getRepeatCount() == 0){
                shortPress = true;
            }
            return true;
        }
    }
    return super.onKeyDown(keyCode, event);
}

@Override
public boolean onKeyUp(int keyCode, KeyEvent event) {
    if (keyCode == KeyEvent.KEYCODE_VOLUME_DOWN) {
        if(shortPress){
            Toast.makeText(this, "shortPress Volume Down", Toast.LENGTH_LONG).show();
        } else {
            //Don't handle longpress here, because the user will have to get his finger back up first
        }
        shortPress = false;
        return true;
    } else if(keyCode == KeyEvent.KEYCODE_VOLUME_UP){
        if(shortPress){
            Toast.makeText(this, "shortPress Volume up", Toast.LENGTH_LONG).show();
        } else {
            //Don't handle longpress here, because the user will have to get his finger back up first
        }
        shortPress = false;
        return true;

    }
    return super.onKeyUp(keyCode, event);
}
票数 4
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：

https://stackoverflow.com/questions/12950215

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