首页
学习
活动
专区
圈层
工具
发布
社区首页 >问答首页 >ABRecordRef的来源(电话簿或icloud)

ABRecordRef的来源(电话簿或icloud)
EN

Stack Overflow用户
提问于 2013-02-28 16:02:45
回答 1查看 834关注 0票数 2

我需要找出ABRecordRef的来源,因为下面的方法从电话簿和icloud返回联系人数组,结果是有两个联系人具有相同的人(名字,姓氏),但具有不同的记录( ABRecordID recordId=ABRecordGetRecordID);?

代码语言:javascript
复制
ABAddressBookRef addressBook;
if ([self isABAddressBookCreateWithOptionsAvailable]) {
    CFErrorRef error = nil;
    addressBook = ABAddressBookCreateWithOptions(NULL,&error);

    ABAddressBookRequestAccessWithCompletion(addressBook, ^(bool granted, CFErrorRef error) {

        dispatch_async(dispatch_get_main_queue(), ^{

            if (error) {

            } else if (!granted) {

            } else {
                CFArrayRef allPeople = ABAddressBookCopyArrayOfAllPeople(addressBook);
                CFIndex nPeople = ABAddressBookGetPersonCount(addressBook);

                for (int i = 0; i < nPeople; i++) {
                    // Get the next address book record.
                    ABRecordRef record = CFArrayGetValueAtIndex(allPeople, i);

                    ABRecordID recordId=ABRecordGetRecordID(record);

                    NSString* firstName = (__bridge_transfer NSString*)ABRecordCopyValue(record,kABPersonFirstNameProperty);
                    NSString* lastName = (__bridge_transfer NSString*)ABRecordCopyValue(record,kABPersonLastNameProperty);

                    CFTypeRef bDayProperty = ABRecordCopyValue((ABRecordRef)record, kABPersonBirthdayProperty);

                    NSDate *birthday;

                    if (ABRecordCopyValue((ABRecordRef)record, kABPersonBirthdayProperty))
                    {
                        birthday=(__bridge NSDate*)bDayProperty;
                    }

                }
                CFRelease(addressBook);

            }
        });
    });
} else {
    // iOS 4/5
    addressBook = ABAddressBookCreate();
    CFRelease(addressBook);
} 
EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2013-02-28 17:28:18

Source of the answer

添加新集合

代码语言:javascript
复制
NSMutableSet *linkedPersonsToSkip = [[NSMutableSet alloc] init];

只需检查每个人

代码语言:javascript
复制
if ([linkedPersonsToSkip containsObject:(__bridge id)(record)]) {
                            continue;
}

NSArray *linked = (__bridge NSArray *) ABPersonCopyArrayOfAllLinkedPeople(record);
if ([linked count] > 1) {
   [linkedPersonsToSkip addObjectsFromArray:linked];
}
票数 1
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/15130397

复制
相关文章

相似问题

领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档