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PHP json_decode JSON_ERROR_SYNTAX
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Stack Overflow用户
提问于 2017-09-22 02:47:23
回答 1查看 2.7K关注 0票数 1

我尝试从这个link加载并解析JSON文件。

但是我有JSON_ERROR_SYNTAX问题和为foreach()提供的无效参数。为什么会发生这种情况?

代码语言:javascript
复制
[{ "Manufacturer": "Toyota", "Sold": 1200, "Month": "2012-11" }, { "Manufacturer": "Ford", "Sold": 1100, "Month": "2012-11" }, { "Manufacturer": "BMW", "Sold": 900, "Month": "2012-11" }, { "Manufacturer": "Benz", "Sold": 600, "Month": "2012-11" }, { "Manufacturer": "GMC", "Sold": 500, "Month": "2012-11" }, { "Manufacturer": "HUMMER", "Sold": 120, "Month": "2012-11" }]

代码语言:javascript
复制
<?php
$url = "http://www.pureexample.com/backend/data/car-sale.json";
$url = file_get_contents($url);
print_r($url);
$url = stripslashes($url);
print_r($url);
$url = str_replace("\n", "", $url);
print_r($url);
$url = iconv('UTF-8', 'UTF-8//IGNORE', utf8_encode($url));
print_r($url);
$url = json_decode($url, true);
// Add this switch to your code
switch (json_last_error())
{
    case JSON_ERROR_NONE:
        echo ' - No errors';
        break;
    case JSON_ERROR_DEPTH:
        echo ' - Maximum stack depth exceeded';
        break;
    case JSON_ERROR_STATE_MISMATCH:
        echo ' - Underflow or the modes mismatch';
        break;
    case JSON_ERROR_CTRL_CHAR:
        echo ' - Unexpected control character found';
        break;
    case JSON_ERROR_SYNTAX:
        echo ' - Syntax error, malformed JSON';
        break;
    case JSON_ERROR_UTF8:
        echo ' - Malformed UTF-8 characters, possibly incorrectly encoded';
        break;
    default:
        echo ' - Unknown error';
        break;
}


foreach($koyim as $data){
echo $data['Manufacturer'];
echo $data['Sold'];
echo $data['Month'];
echo "<br/>";
}
?>

EN

回答 1

Stack Overflow用户

发布于 2017-09-22 03:20:30

您提供的link为UTF-8格式的JSON提供了一个字节顺序标记。显然,json_decode()不能很好地处理这三个无关的字符。解决方案是剥离BOM:

代码语言:javascript
复制
<?php

//see https://stackoverflow.com/a/32185872/500890
function removeBomUtf8($s){
   if(substr($s,0,3)==chr(hexdec('EF')).chr(hexdec('BB')).chr(hexdec('BF'))){
        return substr($s,3);
    }else{
        return $s;
    }
}

$url = "http://www.pureexample.com/backend/data/car-sale.json";
$content = file_get_contents($url);
$clean_content = removeBomUtf8($content);
$decoded = json_decode($clean_content);

//Recovered data
echo "<pre>" . print_r($decoded, TRUE);

我采用了这个解决方案来剥离BOM:https://stackoverflow.com/a/32185872/500890,尽管在互联网上有很多这样的东西。其主要思想是,如果前三个特定字符确实是BOM,则将其去掉。

票数 6
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/46351165

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