文章/答案/技术大牛

发布

社区首页 >问答首页 >neo4j APOC apoc.convertToJson()不能转换{a："dddddd"}

问neo4j APOC apoc.convertToJson()不能转换{a："dddddd"}
EN

Stack Overflow用户

提问于 2022-01-19 16:06:03

回答 1查看 61关注 0票数 0

我试图使用以下方法向节点添加属性

 n.item = apoc.convert.toJson(itemObject)

哪里

itemArrayObjects = {"source":"Blogspot.com","author":"noreply@blogger.com (Unknown)","title":"Elon Musk reveals who bitcoin's creator Satoshi Nakamoto might be","content":"Musk.MARK RALSTON/AFP via Getty Images\r\nElon Musk seems to agree with many that hyper-secret cryptocurrency expert Nick Szabo could be Satoshi Nakamoto, the mysterious creator of the digital currency… [+1467 chars]","publishedAt":"2021-12-29T20:41:00Z","url":"https://techncruncher.blogspot.com/2021/12/elon-musk-reveals-who-bitcoins-creator.html"}

这会导致

Neo4jError: Failed to invoke function `apoc.convert.toJson`: Caused by: java.lang.NullPointerException

在Neo4j浏览器中，这是工作的:返回apoc.convert.toJson({d：“d”，e:"eeee"})

但这不管用：

返回apoc.convert.toJson({"a"："aaaaaa"，"b"："bbbbbb"})

如果我将这些值赋值给密码:param，如下所示：

:param items =>[{source:"Blogspot.com",author:"noreply@blogger.com (Unknown)",title:"Elon Musk reveals who bitcoin's creator Satoshi Nakamoto might be",content:"Musk.MARK RALSTON/AFP via Getty Images\r\nElon Musk seems to agree with many that hyper-secret cryptocurrency expert Nick Szabo could be Satoshi Nakamoto, the mysterious creator of the digital currency… [+1467 chars]",publishedAt:"2021-12-29T20:41:00Z",url:"https://techncruncher.blogspot.com/2021/12/elon-musk-reveals-who-bitcoins-creator.html"},{d:"xxddddd",e:"eeee"},{d:"ddddd",e:"eeee"}]

我知道这是:帕拉姆

{
  "items": [
    {
      "publishedAt": "2021-12-29T20:41:00Z",
      "author": "noreply@blogger.com (Unknown)",
      "source": "Blogspot.com",
      "title": "Elon Musk reveals who bitcoin's creator Satoshi Nakamoto might be",
      "url": "https://techncruncher.blogspot.com/2021/12/elon-musk-reveals-who-bitcoins-creator.html",
      "content": "Musk.MARK RALSTON/AFP via Getty Images
Elon Musk seems to agree with many that hyper-secret cryptocurrency expert Nick Szabo could be Satoshi Nakamoto, the mysterious creator of the digital currency… [+1467 chars]"
    },
    {
      "d": "xxddddd",
      "e": "eeee"
    },
    {
      "d": "ddddd",
      "e": "eeee"
    }
  ]
}

请注意，这些键是双引号"“，这是正确的，这是可行的：

返回apoc.convert.toJson($items)

因此，它似乎有一些幕后转换正在进行。它似乎也有一些不一致的地方，因为它在没有变化的情况下工作。

有人能解释一下这件事吗？

编辑:我实际上是使用neo4j桌面4.2.1和APOC4.2.0本地和neo4j 4.4.2码头图像与APOC 4.4.0.1在数字海洋。不一致之处在于，这在很大程度上是在本地工作的。

neo4j-apoc

neo4j

cypher

回答 1

Stack Overflow用户

发布于 2022-01-21 13:02:45

显然，apoc v4.4.0.1中有一个错误，因为它与apoc.convert.Json()有关，....a修复是在v4.4.0.2中完成的。

票数 0

页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持

原文链接：

https://stackoverflow.com/questions/70773915

复制

相似问题

问neo4j APOC apoc.convertToJson()不能转换{a："dddddd"}
EN

回答 1

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问neo4j APOC apoc.convertToJson()不能转换{a："dddddd"}EN

回答 1

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问neo4j APOC apoc.convertToJson()不能转换{a："dddddd"}
EN