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问urequests.post在micropython esp8266上的烧瓶误差
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Stack Overflow用户

提问于 2021-03-04 05:41:14

回答 1查看 257关注 0票数 2

我只是用烧瓶制作api，在micropython urequests.post上有错误的esp8266，这是我的代码

flask.py

from flask import Flask, request
import os, sys

cert = os.path.join(sys.path[0], 'cert.pem')
key = os.path.join(sys.path[0], 'key.pem')

app = Flask(__name__)

context = (cert, key)

@app.route("/")
def hello():
    return {'data': 'demo'}

@app.route('/demo', methods = ['POST'])
def demo_post():
    content = request.get_json()
    print(content)
    return content

if __name__ == "__main__":
    app.run(host='0.0.0.0', port='5000', debug = True, ssl_context = context)
    #app.run(port='5000', debug = True)

Normal_requests(工作).py

import requests
requests.get('https://example.com/').json()
>>> {'data': 'demo'}
requests.post('https://example.com/demo', json={"a":5,"b":4}).json()
>>> {"a":5,"b":4}

Micropython_urequests(工作).py

import urequests
urequests.get('https://example.com/').json()
>>> {'data': 'demo'}

错误--这行

urequests.post('https://example.com/demo', json={"a":5,"b":4}).json()

错误

Traceback (most recent call last):
  File "/home/pi/programing/myenv/flask/lib/python3.7/site-packages/flask/app.py", line 2464, in __call__
    return self.wsgi_app(environ, start_response)
  File "/home/pi/programing/myenv/flask/lib/python3.7/site-packages/flask/app.py", line 2450, in wsgi_app
    response = self.handle_exception(e)
  File "/home/pi/programing/myenv/flask/lib/python3.7/site-packages/flask/app.py", line 1867, in handle_exception
    reraise(exc_type, exc_value, tb)
  File "/home/pi/programing/myenv/flask/lib/python3.7/site-packages/flask/_compat.py", line 39, in reraise
    raise value
  File "/home/pi/programing/myenv/flask/lib/python3.7/site-packages/flask/app.py", line 2447, in wsgi_app
    response = self.full_dispatch_request()
  File "/home/pi/programing/myenv/flask/lib/python3.7/site-packages/flask/app.py", line 1953, in full_dispatch_request
    return self.finalize_request(rv)
  File "/home/pi/programing/myenv/flask/lib/python3.7/site-packages/flask/app.py", line 1968, in finalize_request
    response = self.make_response(rv)
  File "/home/pi/programing/myenv/flask/lib/python3.7/site-packages/flask/app.py", line 2098, in make_response
    "The view function did not return a valid response. The"
TypeError: The view function did not return a valid response. The function either returned None or ended without a return statement.

请帮帮忙，谢谢！

python

json

python-requests

回答 1

Stack Overflow用户

回答已采纳

发布于 2021-03-04 07:34:06

请查看urequests示例

使用ujson.dumps返回到dict，表示为JSON字符串。

import urequests
import ujson

post_data = ujson.dumps({"a":5,"b":4})

res = urequests.post('https://example.com/demo', headers = {'content-type': 'application/json'}, data = post_data).json()

票数 1

页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持

原文链接：

https://stackoverflow.com/questions/66469231

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