我有下表和样本记录:
create table jtest
(
id int,
jcol json
);
insert into jtest values(1,'{"name":"Jack","address1":"HNO 123"}');
insert into jtest values(1,'{"address2":"STREET1"}');
insert into jtest values(1,'{"address3":"UK"}');
select * from jtest;
id jcol
-------------------------------------------
1 {"name":"Jack","address":"HNO 123 UK"}
1 {"address2":"STREET1"}
1 {"address3":"UK"}预期结果:
id jcol
--------------------------------------------------------------------------------------------
1 {"name":"Jack","address":"HNO 123 UK", "address2":"STREET1", "address3":"UK"}尝试了以下查询:
select id,json_agg(jcol) as jcol
from jtest
group by id;但是得到结果是出乎意料的:
id jcol
--------------------------------------------------------------------------------------------
1 [{"name":"Jack","address":"HNO 123 UK"}, {"address2":"STREET1"}, {"address3":"UK"}] 发布于 2020-12-07 11:38:26
SELECT
id,
json_object_agg(key, value) -- 2
FROM
t,
json_each(jcol) -- 1
GROUP BY idhttps://stackoverflow.com/questions/65180882
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