问如何在矩阵中重新排列列到行？

EN

import numpy as np
t=np.array([[1, 2, 3],
            [4 ,5 ,6],
            [7, 8 ,9]])
result = []
rows,columns = t.shape
for i in range(rows):
    a = np.r_[t[0:rows-i,i],t[rows-1-i,i+1:]]
    pad = int(((rows+columns)-1-len(a))/2)
    a = np.pad(a,(pad,pad), 'constant', constant_values=(0,0))
    result.append(list(a))
print(result)

[[1, 4, 7, 8, 9], [0, 2, 5, 6, 0], [0, 0, 3, 0, 0]]

t=np.array([[1, 2, 3,4],
            [4 ,5 ,6,10]])

[[1, 4, 5, 6, 10], [0, 2, 3, 4, 0]]

A = np.arange(1, 10).reshape(3, 3)

import numpy as np


def get_mat(mat, cnt, col):

    if cnt == mat.shape[0]:
        return col

    for i in range(cnt):
        col.append(0)

    for i in range(0, len(mat) - cnt):
        m = mat[i]
        col.append(m[cnt])

    for r in m[cnt+1:]:
        col.append(r)

    for i in range(cnt):
        col.append(0)

    return get_mat(mat, cnt+1, col)


A = np.arange(1, 10).reshape(3, 3)

cols = []

res = get_mat(A, 0, cols)

res = np.reshape(res, (3, 5))
print(res)

[[1 4 7 8 9]
 [0 2 5 6 0]
 [0 0 3 0 0]]

input_array=[[1,2,3],[4,5,6],[7,8,9]] #input array
row=len(input_array) #no of rows in array
col=len(input_array[0]) #no of columns in array
for i in range(0,col): #iterating for each head value
    turn=row-i
    for j in range(0,turn): #itearing and taking turn
        if j==0:
            for l in range(i): #for printing zeros in the beginning 
                print(0,end=" ")   
        if j<=row:
            print(input_array[j][i],end=" ")
        if j==turn-1: #taking turn
            for k in range(i+1,row):
                print(input_array[j][k],end=" ")
            for l in range(i): #for printing zeros in the beginning
                print(0,end=" ")
    print("\n")  #line break