在GoogleSql Bigquery中使用where子句和Union
在GoogleSql Bigquery中使用where子句和Union
提问于 2020-05-09 10:29:56
我正在尝试合并两个比较匹配字段的表，但我正在更正以下错误：- "SQL_ANALYSIS_ERROR:无法识别的名称: t2 (行: 87，列: 121)“，其中第二个表重命名了t2
这是我的密码：-
CREATE OR REPLACE TABLE table_1 OPTIONS (
quota_accounting_owner='sxxx@gmail.com')
AS
SELECT * FROM
(
SELECT * EXCEPT(fate_result), CAST(fate_result AS STRING) AS fate_result FROM table_1 AS t1 WHERE t2.e_id <> t1.e_id
UNION DISTINCT
SELECT * EXCEPT(fate_result), CAST(fate_result AS STRING) AS fate_result FROM table_2 AS t2
);回答 1
Stack Overflow用户
回答已采纳
发布于 2020-05-09 10:50:10
您可以使用NOT EXISTS只选择在table_2中没有匹配e_id的table_1行
CREATE OR REPLACE TABLE table_1 OPTIONS (
quota_accounting_owner='sxxx@gmail.com')
AS
SELECT * FROM
(
SELECT * EXCEPT(fate_result), CAST(fate_result AS STRING) AS fate_result
FROM table_1 AS t1
WHERE NOT EXISTS (
SELECT 1
FROM table_2 AS t2
WHERE t2.e_id = t1.e_id
)
UNION DISTINCT
SELECT * EXCEPT(fate_result), CAST(fate_result AS STRING) AS fate_result
FROM table_2 AS t2
);编辑不存在将是标准的正确选择，但是看到下面的注释，它将引发一个错误。所以不是在可能会更好
CREATE OR REPLACE TABLE table_1 OPTIONS (
quota_accounting_owner='sxxx@gmail.com')
AS
SELECT * FROM
(
SELECT * EXCEPT(fate_result), CAST(fate_result AS STRING) AS fate_result
FROM table_1 AS t1
WHERE t1.e_id NOT IN (
SELECT t2.ed_id
FROM table_2 AS t2
)
UNION DISTINCT
SELECT * EXCEPT(fate_result), CAST(fate_result AS STRING) AS fate_result
FROM table_2 AS t2
);页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/61695272
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