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问从php array_push和循环创建javascript文件
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Stack Overflow用户

提问于 2021-04-20 15:49:04

回答 1查看 34关注 0票数 0

我在php中生成了如下数组：

array_push($json, (object)[
  'location_lat' => $spot_lat,
  'location_lng' => $spot_lng,
  'cat' => $spot_category,
  'additional' => $spot_additional
]);

这个代码在我的“while”循环中。在我的功能结束时，我要做的是：

  $fp = fopen('my-path/spots.js', 'w');
  $addressPoints = json_encode($json);
  fwrite($fp, $addressPoints);
  fclose($fp);

所有的工作都很好，我得到了一个很好的spots.js文件，如下所示：

[{"location_lat":"49.6149366","location_lng":"22.2754669","cat":"na-dziko","additional":["is_verified","paid","bike","fishing","pitch","shop","river","lake","forest","buildings","playground","sanitary","wifi","barbecue","kitchen","year","electricity"]},{"location_lat":"49.4257138","location_lng":"20.4740524","cat":"kempingi-i-pola-namiotowe","additional":["paid","bike","trails","river","forest","mountains","sanitary","barbecue","kitchen","electricity"]},{"location_lat":"44.52625","location_lng":"1.71944","cat":"kempingi-i-pola-namiotowe","additional":["paid","bike","pool","fishing","water_sport","trails","climber","6","Array","shop","river","forest","mountains","4","Array","sanitary","wifi","kitchen","restaurant","electricity","5","Array"]}]

但问题是，我不知道如何将这个数组设置为变量？我需要生成这样的.js文件：

var myCustomVariable = [{"location_lat":"49.6149366","location_lng":"22.2754669","cat":"na-dziko","additional":["is_verified","paid","bike","fishing","pitch","shop","river","lake","forest","buildings","playground","sanitary","wifi","barbecue","kitchen","year","electricity"]},{"location_lat":"49.4257138","location_lng":"20.4740524","cat":"kempingi-i-pola-namiotowe","additional":["paid","bike","trails","river","forest","mountains","sanitary","barbecue","kitchen","electricity"]},{"location_lat":"44.52625","location_lng":"1.71944","cat":"kempingi-i-pola-namiotowe","additional":["paid","bike","pool","fishing","water_sport","trails","climber","6","Array","shop","river","forest","mountains","4","Array","sanitary","wifi","kitchen","restaurant","electricity","5","Array"]}]

解决办法可能很简单，但我做不到。

php

javascript

回答 1

Stack Overflow用户

回答已采纳

发布于 2021-04-20 16:08:48

$addressPoints是一个字符串。因此，您可以简单地向其添加所需的var声明：

$addressPoints = 'var myCustomVariable = ' . json_encode($json);

票数 2

页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持

原文链接：

https://stackoverflow.com/questions/67182224

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