blocks|key|1734954|text|linux-gate.so并不是真正的共享库，而是内核的一部分，它的作用类似于共享库，并使快速系统调用成为可能。ld-linux.so是一段代码，它使加载其他共享库成为可能。libc.so是C库，包含像printf和strcpy这样的标准函数。|type|ordered-list-item|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1734955|main不属于任何库。它属于您的程序，因为它的组装版本完全存储在test二进制文件中。|1734956|return不是函数，而是C语言结构。|1734957|不，它还链接在libgcc中，它显然不是您系统上的共享库(否则它会出现)和一些启动代码。g%2B%2B还将链接到libstdc%2B%2B.so+(+C%2B%2B标准库)和libm.so+(C标准库的数学部分)中。|1734958|unstyled|entityMap^0|0|D|1K|B|2F|7|2T|6|30|6|0|0|4|W|4|0|0|6|0|7|6|18|3|1G|C|23|7|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]|$9|T|A|U|B|C]|$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|Z|8|@$9|10|A|11|B|C]|$9|12|A|13|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|14|8|@$9|15|A|16|B|C]]|D|@]|E|$]]|$1|J|3|K|5|6|7|17|8|@$9|18|A|19|B|C]|$9|1A|A|1B|B|C]|$9|1C|A|1D|B|C]|$9|1E|A|1F|B|C]]|D|@]|E|$]]|$1|L|3|-4|5|M|7|1G|8|@]|D|@]|E|$]]]|N|$]]

<ol>
<li><code>linux-gate.so</code> isn't really a shared lib, but a part of the kernel that acts like one and makes fast system calls possible. <code>ld-linux.so</code> is a piece of code that makes loading other shared libraries possible. <code>libc.so</code> is the C library, containing standard functions like <code>printf</code> and <code>strcpy</code>.</li>
<li><code>main</code> doesn't belong to any library. It belongs to your program, in the sense that its assembled version is stored entirely in the <code>test</code> binary file.</li>
<li><code>return</code> is not a function but a C language construct.</li>
<li>No, it also links in <code>libgcc</code>, which is apparently not a shared library on your system (or it would show up) and some startup code. <code>g++</code> would additionally link in <code>libstdc++.so</code> (the C++ standard library) and <code>libm.so</code> (the math part of the C standard library).</li>
</ol>

blocks|key|2931814|text|linux-gate是一个虚拟共享对象，充当内核内系统调用的连接。libc是glibc，它提供诸如printf()等功能。ld-linux是glibc加载器，它允许加载其他共享对象。|type|ordered-list-item|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2931815|main()属于您的代码。它由crt1.o调用，由gcc将其链接到可执行文件中(具体地说是ld+)。|2931816|return不是一个函数，而是一个语言结构，所以gcc将它直接转换为包含在对象(最终是可执行的)文件中的代码。另外，main()返回的值被crt1.o捕获并转换为程序结果代码。|2931817|unstyled|entityMap^0|0|A|X|4|1D|8|1P|8|0|0|6|F|6|0|0|6|1M|6|1X|6|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]|$9|R|A|S|B|C]|$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|V|8|@$9|W|A|X|B|C]|$9|Y|A|Z|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|10|8|@$9|11|A|12|B|C]|$9|13|A|14|B|C]|$9|15|A|16|B|C]]|D|@]|E|$]]|$1|J|3|-4|5|K|7|17|8|@]|D|@]|E|$]]]|L|$]]

<ol>
<li><code>linux-gate</code> is a virtual shared object that acts as a connection to system calls within the kernel. <code>libc</code> is glibc, which provides functions such as <code>printf()</code> and so on. <code>ld-linux</code> is the glibc loader, which allows loading of other shared objects.</li>
<li><code>main()</code> belongs to your code. It is called by <code>crt1.o</code> which is linked into the executable by gcc (well, ld specifically).</li>
<li><code>return</code> is not a function but rather a language construct, so gcc turns it directly into code contained within the object (and eventually executable) file. As an aside, the value returned from <code>main()</code> is caught by <code>crt1.o</code> and turned into a program result code.</li>
</ol>

blocks|key|1735011|text|关于linux如何执行我的main()？的详细描述，您将在那里找到答案，可能还有更多！|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1735012|entityMap|0|LINK|mutability|MUTABLE|url|http://linuxgazette.net/84/hawk.html^0|2|I|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

Exelent description about <a href="http://linuxgazette.net/84/hawk.html" rel="nofollow">how does linux execute my main()?</a> There you will find the answer and probably a lot more!

blocks|key|3288438|text|linux-gate是一个虚拟库，提供对系统功能的访问。它的全名是Linux虚拟动态共享对象。它是libc使用的。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3288439|libc是C运行时。它实际上被称为main()。(如果不使用任何C函数，就可以绕过它。)|3288440|ld-linux是动态链接器，它实际上知道如何为您加载和调用C运行时。|3288441|main住在test.o，而不是图书馆。|3288442|return是关键字，而不是函数。它指示编译器发出代码，以使函数返回其调用方的控制。|3288443|entityMap^0|0|A|1D|4|0|0|4|0|0|8|0|0|4|0|0|6|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]|$9|S|A|T|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|X|8|@$9|Y|A|Z|B|C]]|D|@]|E|$]]|$1|J|3|K|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@]|E|$]]|$1|L|3|M|5|6|7|13|8|@$9|14|A|15|B|C]]|D|@]|E|$]]|$1|N|3|-4|5|6|7|16|8|@]|D|@]|E|$]]]|O|$]]

<code>linux-gate</code> is a virtual library that provides access to system functions. Its full name is the Linux Virtual Dynamic Shared Object. It's used by <code>libc</code>.

<code>libc</code> is the C run time. It's what actually calls main() for you. (It's possible to bypass this if you don't use any C functions.)

<code>ld-linux</code> is the dynamic linker, which actually knows how to load and call the C run time for you.

<code>main</code> lives in test.o, not in a library.

<code>return</code> is a keyword, not a function. It directs the compiler to emit code to cause the function to return control to its caller.

blocks|key|3288510|text|ld-linux.so提供了帮助ldd工作的魔力。libc.so是C运行时库的一部分。除其他外，运行库包含调用main的实际入口点。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3288511|main由您的代码提供。return不是函数，它是C语言中的关键字。|3288512|entityMap^0|0|B|G|3|P|7|1J|4|0|0|4|C|6|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]|$9|M|A|N|B|C]|$9|O|A|P|B|C]|$9|Q|A|R|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|S|8|@$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@]|E|$]]|$1|H|3|-4|5|6|7|X|8|@]|D|@]|E|$]]]|I|$]]

<code>ld-linux.so</code> provides the magic that helps <code>ldd</code> work.
<code>libc.so</code> is part of the C runtime library. Among other things, the runtime library contains the actual entry point that calls <code>main</code>.

<code>main</code> is provided by your code.
<code>return</code> is not a function, it's a keyword in the C language.

My code is in test.c:

<pre><code>int main(){
return 0;
}
</code></pre>

The dynamically shared libraries the executable compiled from it depends on are:

<pre><code>$ gcc -o test test.c
$ ldd test
 linux-gate.so.1 =&gt; (0x00783000)
 libc.so.6 =&gt; /lib/libc.so.6 (0x00935000)
 /lib/ld-linux.so.2 (0x00ea5000)
</code></pre>

<ol>
<li>I was wondering what roles the three libraries are playing?</li>
<li>Which library does the function <code>main</code> belong to? /lib/libc.so.6?</li>
<li>Which library does <code>return</code> belong to? /lib/libc.so.6?</li>
<li>Are the three libraries all that are dynamically linked by default by gcc? </li>
<li>How can I find out static libraries that gcc links to by default?</li>
</ol>

Thanks!

Libraries that are linked by default

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我的代码正在测试中：int main(){return 0;}从它编译的可执行文件所依赖的动态共享库是：$ gcc -o test test.c$ ldd test    linux-gate.so.1 =>  (0x00783000)    libc.so.6 => /lib/libc.so.6 (0x00935000)    /lib/ld-linux.so.2 (0x00ea5000)我想知

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