我有两个表,其结构如下:
表1:显示玩家尝试的次数。
Player_id, n_tries, date表2:显示玩家的点击次数。
Player_id, n_hits, date最后,我希望有一个球员今天的命中率(尝试与命中),以及今天到一周前的点击率的增加/减少。我希望结果按(今天)命中下降的百分比排序。因此,例如,如果我们有一个id = 1的播放器和一个id = 2的播放器,那么这个数据如下:
表1:
1, 10, "2012-10-14"
2, 13, "2012-10-14"
1, 20, "2012-10-7"
2, 15, "2012-10-7"表2:
1, 5, "2012-11-14"
2, 10, "2012-11-14"
1, 0, "2012-11-7"
2, 3, "2012-11-7"我需要最后证明这一点:
Player_id,%命中率(今天),点击率差(今天和一周前)
2 77% +233%
1 50% +100% (actually is infinite -> (5 - 0)/0 )我有从两个表中获取值的查询:
第一个表-尝试次数:
SELECT player_id, date, sum(n_tries)
FROM player_tries
WHERE (d_date = CURDATE() OR d_date = DATE_SUB(CURDATE(), INTERVAL 7 DAY))
GROUP BY date, player_id
ORDER BY player_id, date我做一个求和(N_tries),因为一个球员可以有多行的尝试为特定的一天。
第二表-点击次数:
SELECT player_id, date, sum(n_hits)
FROM player_hits
WHERE (d_date = CURDATE() OR d_date = DATE_SUB(CURDATE(), INTERVAL 7 DAY))
GROUP BY date, player_id
ORDER BY player_id, date因此,我的问题是:如果从第一个查询中得到一个结果列表,如下所示:
Player_id, date, n_tries
1 2012-11-07 20
1 2012-11-14 10
2 2012-11-07 15
2 2012-11-14 13在第二张桌子上,我得到了这个:
Player_id, date, n_hits
1 2012-11-07 0
1 2012-11-14 5
2 2012-11-07 3
2 2012-11-14 10什么是最好的方式,能够混合这些结果,并能够有某种结构,是按%点击(今天)。
发布于 2012-11-14 11:24:13
选择今天和一周前的点击:
select h1.player_id, `h1.date`,
sum(h1.hits) as hits_today,
sum(h2.hits) as hits_last_week
from player_hits h1
left join player_hits h2 on h2.player_id = h1.player_id
and `h2.date` = date_sub(`h1.date`, interval 7 days)
group by h1.player_id, `h1.date`;如果仅希望在一周前有相应条目时才需要行,则将左侧联接替换为内部联接。
tries表的select看起来是等效的。
首先,以player_id作为键,将结果选择到数组中。
$hits_array = array();
$result = mysqli_query(...);
while ($row = mysqli_fetch_assoc($result)) {
$player = $row['player_id'];
$hits_array[$player] = $row['hits'];
}您对尝试表也是如此。
现在可以加入player_id键上的两个数组:
foreach ($hits_array as $player => $hits) {
echo "$player " . ($hits / $tries[$key]) . "\n";
}https://stackoverflow.com/questions/13377516
复制相似问题