我有一张桌子:
|NAME(Key) | LOGIN_DATE |
|----------------|---------------------|
|mark | 2012-10-10 10:35:00 |
|mark | 2012-10-10 10:40:00 |
|mark | 2012-10-10 10:45:00 |我想知道如何找出最后一次约会和第一次约会的区别:
|NAME | TIME_DIFF |
|----------------|---------------------|
|mark | 10 minutes |我该怎么做?
发布于 2014-04-03 15:27:50
SELECT name
, SEC_TO_TIME( MAX(TIME_TO_SEC(login_date))
- MIN(TIME_TO_SEC(login_date))
) x
FROM my_table
GROUP
BY name;发布于 2014-04-03 15:20:43
select
name,
concat( timestampdiff( minute,
min( login_date ),
max( login_date ) ),
' minutes'
) as 'login duration'
from my_table
group by name发布于 2014-04-03 15:20:30
SELECT MIN(`LOGIN_DATE`), MAX(`LOGIN_DATE`) WHERE `NAME(Key)` = 'mark';https://stackoverflow.com/questions/22841955
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