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社区首页 >问答首页 >Arduino矩阵按钮框,一键按下即可识别为同时按下四键

Arduino矩阵按钮框,一键按下即可识别为同时按下四键
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Stack Overflow用户
提问于 2019-04-27 02:42:35
回答 1查看 351关注 0票数 1

我试着在这个示例代码中用更少的按钮来做矩阵按钮框:

代码草图和接线方案:

https://github.com/AM-STUDIO/32-FUNCTION-BUTTON-BOX

https://imgur.com/xN93GHW

这就是我想要做的:

https://imgur.com/kA7p9gC

我已经做了这个设置,但当我按下一个键时,它被识别为同时按下了四个键。我认为它一定是相关的行和列。我只是arduino世界的初学者。如果有人能帮上忙我会很感激的。

我试着在代码中改变行和cols的大小,并互相改变行和cols的引脚,但都不起作用。

代码语言:javascript
复制
//BUTTON BOX 
//USE w ProMicro
//Tested in WIN10 + Assetto Corsa
//AMSTUDIO
//20.8.17

#include <Keypad.h>
#include <Joystick.h>

#define ENABLE_PULLUPS
#define NUMROTARIES 4
#define NUMBUTTONS 24
#define NUMROWS 5
#define NUMCOLS 5


byte buttons[NUMROWS][NUMCOLS] = {
  {0,1,2,3,4},
  {5,6,7,8,9},
  {10,11,12,13,14},
  {15,16,17,18,19},
  {20,21,22,23},
};

struct rotariesdef {
  byte pin1;
  byte pin2;
  int ccwchar;
  int cwchar;
  volatile unsigned char state;
};

rotariesdef rotaries[NUMROTARIES] {
  {0,1,24,25,0},
  {2,3,26,27,0},
  {4,5,28,29,0},
  {6,7,30,31,0},
};

#define DIR_CCW 0x10
#define DIR_CW 0x20
#define R_START 0x0

#ifdef HALF_STEP
#define R_CCW_BEGIN 0x1
#define R_CW_BEGIN 0x2
#define R_START_M 0x3
#define R_CW_BEGIN_M 0x4
#define R_CCW_BEGIN_M 0x5
const unsigned char ttable[6][4] = {
  // R_START (00)
  {R_START_M,            R_CW_BEGIN,     R_CCW_BEGIN,  R_START},
  // R_CCW_BEGIN
  {R_START_M | DIR_CCW, R_START,        R_CCW_BEGIN,  R_START},
  // R_CW_BEGIN
  {R_START_M | DIR_CW,  R_CW_BEGIN,     R_START,      R_START},
  // R_START_M (11)
  {R_START_M,            R_CCW_BEGIN_M,  R_CW_BEGIN_M, R_START},
  // R_CW_BEGIN_M
  {R_START_M,            R_START_M,      R_CW_BEGIN_M, R_START | DIR_CW},
  // R_CCW_BEGIN_M
  {R_START_M,            R_CCW_BEGIN_M,  R_START_M,    R_START | DIR_CCW},
};
#else
#define R_CW_FINAL 0x1
#define R_CW_BEGIN 0x2
#define R_CW_NEXT 0x3
#define R_CCW_BEGIN 0x4
#define R_CCW_FINAL 0x5
#define R_CCW_NEXT 0x6

const unsigned char ttable[7][4] = {
  // R_START
  {R_START,    R_CW_BEGIN,  R_CCW_BEGIN, R_START},
  // R_CW_FINAL
  {R_CW_NEXT,  R_START,     R_CW_FINAL,  R_START | DIR_CW},
  // R_CW_BEGIN
  {R_CW_NEXT,  R_CW_BEGIN,  R_START,     R_START},
  // R_CW_NEXT
  {R_CW_NEXT,  R_CW_BEGIN,  R_CW_FINAL,  R_START},
  // R_CCW_BEGIN
  {R_CCW_NEXT, R_START,     R_CCW_BEGIN, R_START},
  // R_CCW_FINAL
  {R_CCW_NEXT, R_CCW_FINAL, R_START,     R_START | DIR_CCW},
  // R_CCW_NEXT
  {R_CCW_NEXT, R_CCW_FINAL, R_CCW_BEGIN, R_START},
};
#endif

byte rowPins[NUMROWS] = {21,20,19,18,15}; 
byte colPins[NUMCOLS] = {14,16,10,9,8}; 

Keypad buttbx = Keypad( makeKeymap(buttons), rowPins, colPins, NUMROWS, NUMCOLS); 

Joystick_ Joystick(JOYSTICK_DEFAULT_REPORT_ID, 
  JOYSTICK_TYPE_JOYSTICK, 32, 0,
  false, false, false, false, false, false,
  false, false, false, false, false);

void setup() {
  Joystick.begin();
  rotary_init();}

void loop() { 

  CheckAllEncoders();

  CheckAllButtons();

}

void CheckAllButtons(void) {
      if (buttbx.getKeys())
    {
       for (int i=0; i<LIST_MAX; i++)   
        {
           if ( buttbx.key[i].stateChanged )   
            {
            switch (buttbx.key[i].kstate) {  
                    case PRESSED:
                    case HOLD:
                              Joystick.setButton(buttbx.key[i].kchar, 1);
                              break;
                    case RELEASED:
                    case IDLE:
                              Joystick.setButton(buttbx.key[i].kchar, 0);
                              break;
            }
           }   
         }
     }
}


void rotary_init() {
  for (int i=0;i<NUMROTARIES;i++) {
    pinMode(rotaries[i].pin1, INPUT);
    pinMode(rotaries[i].pin2, INPUT);
    #ifdef ENABLE_PULLUPS
      digitalWrite(rotaries[i].pin1, HIGH);
      digitalWrite(rotaries[i].pin2, HIGH);
    #endif
  }
}


unsigned char rotary_process(int _i) {
   unsigned char pinstate = (digitalRead(rotaries[_i].pin2) << 1) | digitalRead(rotaries[_i].pin1);
  rotaries[_i].state = ttable[rotaries[_i].state & 0xf][pinstate];
  return (rotaries[_i].state & 0x30);
}

void CheckAllEncoders(void) {
  for (int i=0;i<NUMROTARIES;i++) {
    unsigned char result = rotary_process(i);
    if (result == DIR_CCW) {
      Joystick.setButton(rotaries[i].ccwchar, 1); delay(50); Joystick.setButton(rotaries[i].ccwchar, 0);
    };
    if (result == DIR_CW) {
      Joystick.setButton(rotaries[i].cwchar, 1); delay(50); Joystick.setButton(rotaries[i].cwchar, 0);
    };
  }
}
EN

回答 1

Stack Overflow用户

发布于 2019-04-27 17:44:57

你能提供你实际使用的代码,而不是你所基于的另一个项目的代码吗?这样我们就可以分析你的代码做了什么。否则,我们将提供一些你可能已经尝试过的建议。

也就是说,您将设置修改为此了吗?

代码语言:javascript
复制
#define NUMBUTTONS 18
#define NUMROWS 4
#define NUMCOLS 5


byte buttons[NUMROWS][NUMCOLS] = {
  {0,1,2,3,4},
  {5,6,7,8,9},
  {10,11,12,13,14},
  {15,16,17}
};

您还需要确保这些与您的布线对齐:

代码语言:javascript
复制
byte rowPins[NUMROWS] = {21,20,19,18,15}; 
byte colPins[NUMCOLS] = {14,16,10,9,8}; 

如果这还不能解决问题,那么“按下的”按钮是在一列中还是在一行中?

票数 0
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/55873340

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