问生成随机和唯一的字符串xslt

EN

<?xml version='1.0'?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<!-- Replace <xyzzy> with <generalization xml:id="unique ID"> -->
<xsl:template match="xyzzy">
  <generalization>
    <xsl:apply-templates select="@*"/>
    <xsl:attribute name="xml:id"><xsl:value-of select="generate-id()"/></xsl:attribute>
    <xsl:apply-templates/>
  </generalization>
</xsl:template>

<!-- Copy everything else straight thru -->
<xsl:template match="node( ) | @*">
    <xsl:copy><xsl:apply-templates select="@*|node()"/></xsl:copy>
</xsl:template>

</xsl:stylesheet>

<?xml version='1.0' encoding='ASCII'?>
<root>
 <xyzzy/>
 <xyzzy a="b">
  <xyzzy xml:id="non-unique-id"/>
 </xyzzy>
</root>

<?xml version="1.0"?>
<root>
 <generalization xml:id="idp28972496"/>
 <generalization a="b" xml:id="idp28945920">
  <generalization xml:id="idp28946416"/>
 </generalization>
</root>

<!-- language: lang-xml -->
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:xs="http://www.w3.org/2001/XMLSchema"
    xmlns:kh="https://github.com/kohsah"
    exclude-result-prefixes="xs xd"
    version="2.0">
    <xsl:function name="kh:shortRandom">
        <xsl:variable name="mxml">
            <node/>
        </xsl:variable>
        <xsl:sequence select="generate-id($mxml//node)"/>
    </xsl:function>

    <xsl:function name="kh:longRandom">
        <xsl:sequence select="concat(kh:shortRandom(), kh:shortRandom(), kh:shortRandom(), kh:shortRandom())"></xsl:sequence>
    </xsl:function>

    <xsl:template match="/">
        <test>
            <randomId><xsl:value-of select="kh:shortRandom()"/></randomId>
            <guid><xsl:value-of select="kh:longRandom()"/></guid>
        </test>
    </xsl:template>

</xsl:stylesheet>