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问在html烧瓶中打印时获取unicode错误
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Stack Overflow用户

提问于 2015-07-08 09:23:38

回答 1查看 158关注 0票数 0

在html瓶中打印时得到unnicode错误。这是我的密码。

{% if(backpaths) %}
{%   for n in backpaths:%}
{%      print '%s'%n %}
</br>
{%   endfor %}
{% endif %}

我试着使用n.decode('utf-8')，但是它没有工作，并得到了相同的错误

backpaths设置为：

['1\xe6\x9c\x89 --(HYPER)--> quantifier={indefinite|\xe4\xb8\x8d\xe5\xae\x9a\xe6\x8c\x87} --(HYPO)--> \xe6\x9c\x89 ', '2\xe6\x9c\x89 --(HYPER)--> exist|\xe5\xad\x98\xe5\x9c\xa8 --(HYPO)--> \xe6\x9c\x89 ']

这是回溯

(most recent call last):
  File "/usr/local/lib/python2.7/dist-packages/flask/app.py", line 1836, in __call__
    return self.wsgi_app(environ, start_response)
  File "/usr/local/lib/python2.7/dist-packages/flask/app.py", line 1820, in wsgi_app
    response = self.make_response(self.handle_exception(e))
  File "/usr/local/lib/python2.7/dist-packages/flask/app.py", line 1403, in handle_exception
    reraise(exc_type, exc_value, tb)
  File "/usr/local/lib/python2.7/dist-packages/flask/app.py", line 1817, in wsgi_app
    response = self.full_dispatch_request()
  File "/usr/local/lib/python2.7/dist-packages/flask/app.py", line 1477, in full_dispatch_request
    rv = self.handle_user_exception(e)
  File "/usr/local/lib/python2.7/dist-packages/flask/app.py", line 1381, in handle_user_exception
    reraise(exc_type, exc_value, tb)
  File "/usr/local/lib/python2.7/dist-packages/flask/app.py", line 1475, in full_dispatch_request
    rv = self.dispatch_request()
  File "/usr/local/lib/python2.7/dist-packages/flask/app.py", line 1461, in dispatch_request
    return self.view_functions[rule.endpoint](**req.view_args)
  File "/home/ganchimeg/FlaskApp/FlaskApp/__init__.py", line 125, in homepage
    return render_template('index.html', backpaths=successPaths)
  File "/usr/local/lib/python2.7/dist-packages/flask/templating.py", line 128, in render_template
    context, ctx.app)
  File "/usr/local/lib/python2.7/dist-packages/flask/templating.py", line 110, in _render
    rv = template.render(context)
  File "/usr/local/lib/python2.7/dist-packages/jinja2/environment.py", line 969, in render
    return self.environment.handle_exception(exc_info, True)
  File "/usr/local/lib/python2.7/dist-packages/jinja2/environment.py", line 742, in handle_exception
    reraise(exc_type, exc_value, tb)
  File "/home/ganchimeg/FlaskApp/FlaskApp/templates/index.html", line 31, in top-level template code
    {{      n }}
UnicodeDecodeError: 'ascii' codec can't decode byte 0xe6 in position 16: ordinal not in range(128)

unicode

flask

回答 1

Stack Overflow用户

回答已采纳

发布于 2015-07-08 09:44:17

您没有Unicode字符串，您有字节字符串。Python试图使用标准的ASCII编解码器隐式解码这些代码。明确地解码它们：

{% if(backpaths) %}
{%   for n in backpaths:%}
{{       n.decode('utf8') }}
</br>
{%   endfor %}
{% endif %}

如果您将backpaths传递到已准备好解码的模板中，情况会更好。

票数 0

页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持

原文链接：

https://stackoverflow.com/questions/31288540

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