为了报告的目的和扁平数据,我想加入包含与术语相关信息的所有WordPress表。
我真的不经常使用join语句,所以我不知道怎么做。我猜它会是这样的:
SELECT wp_terms.term_id, wp_terms.name, wp_term.slug, wp_term_relationships.object_id, wp_term_relationships.term_taxonomy_id, wp_term_taxonomy.term_id, wp_term_taxonomy.taxonomy, wp_term_taxonomy.description, wp_term_taxonomy.parent.parent, wp_termmeta.term_id, wp_termmeta.meta_key, wp_termmeta.meta_value.
FROM wp_terms, wp_term_relationships, wp_term_taxonomy, wp_termmeta
LEFT JOIN wp_term_relationships ON wp_terms.term_id = wp_term_relationships.term_taxonomy_id
LEFT JOIN wp_term_taxonomy ON term_taxonomy_id
LEFT JOIN wp_termmeta on term_id; 任何帮助都是非常感谢的。
发布于 2017-03-29 12:37:33
我只是解决了你的问题。看看这是不是你需要的。
SELECT wp_terms.term_id, wp_terms.name, wp_term_relationships.object_id, wp_term_relationships.term_taxonomy_id, wp_term_taxonomy.term_id, wp_term_taxonomy.taxonomy, wp_term_taxonomy.description, wp_term_taxonomy.parent, wp_termmeta.term_id, wp_termmeta.meta_key, wp_termmeta.meta_value
FROM wp_terms
LEFT JOIN wp_term_relationships ON wp_terms.term_id = wp_term_relationships.term_taxonomy_id
LEFT JOIN wp_term_taxonomy ON wp_term_taxonomy.term_taxonomy_id = wp_term_relationships.term_taxonomy_id
LEFT JOIN wp_termmeta on wp_termmeta.term_id = wp_terms.term_idhttps://stackoverflow.com/questions/43093571
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