Python：@属性装饰器无限循环初始化时？
Python：@属性装饰器无限循环初始化时？
提问于 2018-04-23 13:17:19
Python版本是3.6.5.。我正在学习如何正确地为我的@decorator使用class Duck语法糖。但似乎我做错了什么，我的qq_duck死于过热。下面是演示：
class Duck(object):
def __init__(self, name):
self.name = name
@property
def name(self):
print("Quack! My name is", self.name)
@name.setter
def name(self, name):
print("I've decided to change my name into", name, ".")
print("So please call me", name, "from now on! Quack!")
self.name = name航站楼：
qq_duck = Duck("QQ")
I've decided to change my name into QQ .
So please call me QQ from now on! Quack!
I've decided to change my name into QQ .
So please call me QQ from now on! Quack!
I've decided to change my name into QQ .
So please call me QQ from now on! Quack!
...
Traceback (most recent call last):
File "<input>", line 1, in <module>
File "<input>", line 3, in __init__
File "<input>", line 13, in name
File "<input>", line 13, in name
File "<input>", line 13, in name
[Previous line repeated 488 more times]
File "<input>", line 11, in name
RecursionError: maximum recursion depth exceeded while calling a Python object请帮帮我..。
回答 2
Stack Overflow用户
回答已采纳
发布于 2018-04-23 13:19:36
当您分配self.name = name时，setter函数会调用它自己。这确实会导致无限递归。
解决办法可能是：
class Duck(object):
def __init__(self, name):
self._name = name
@property
def name(self):
print("Quack! My name is", self._name)
# here you usually return the data member...
return self._name
@name.setter
def name(self, name):
print("I've decided to change my name into", name, ".")
print("So please call me", name, "from now on! Quack!")
self._name = name注意成员self._name与属性self.name是如何不同的。
Stack Overflow用户
发布于 2018-04-23 13:19:23
您的self.name所做的是调用您刚刚定义的属性。但这是它最初所称的，所以它将无限循环。
该代码可表示为：
self.name = "something" + ("something" + ("something" + ...[on to infinity!]...) )页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/49982126
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