问如何按长度对列表进行排序，然后按字母顺序进行反向排序

EN

a = list(reversed(sorted(a, key=lambda x: (-len(x), x))))

In [301]: a                                                                                                                                        
Out[301]: ['b', 'a', 'zzz', 'ddd', 'ccc']

import functools

def customsort(a, b):
    if len(a) != len(b):
        return -1 if len(a) < len(b) else 1
    else:
        if a < b:
            return 1
        elif a > b:
            return -1
        else:
            return 0

def main():
    a=['a','b','zzz','ccc','ddd']
    a.sort(key=functools.cmp_to_key(customsort))
    print(a)

main()

['b', 'a', 'zzz', 'ddd', 'ccc']

#before sorting
a = ['a', 'b', 'zzz', 'ccc', 'ddd']

#after sorting
a = ['b', 'a', 'zzz', 'ddd', 'ccc']

a.sort(reverse=True)
a.sort(key=len)