使用curl PHP获取API
使用curl PHP获取API
提问于 2020-08-04 23:35:41
我想从https://www.travel-advisory.info/api获取API，然后我已经写好了代码。
$curl = new CurlService();
$response = $curl->to('https://www.travel-advisory.info/api')->get();
throw_if(!$response, Exception::class, 'Terjadi kesalahan: Data tidak dapat diperoleh');
$data = json_decode($response);
echo $data->data;这是来自API的示例响应
"data": {
"AD": {
"iso_alpha2": "AD",
"name": "Andorra",
"continent": "EU",
"advisory": {
"score": 2.79999999999999982236431605997495353221893310546875,
"sources_active": 4,
"message": "",
"updated": "2020-08-04 07:21:19",
"source": "https://www.travel-advisory.info/andorra"
}
},
"AE": {
"iso_alpha2": "AE",
"name": "United Arab Emirates",
"continent": "AS",
"advisory": {
"score": 3.100000000000000088817841970012523233890533447265625,
"sources_active": 7,
"message": "",
"updated": "2020-08-04 07:21:19",
"source": "https://www.travel-advisory.info/united-arab-emirates"
}
},
"AF": {
"iso_alpha2": "AF",
"name": "Afghanistan",
"continent": "AS",
"advisory": {
"score": 5,
"sources_active": 10,
"message": "",
"updated": "2020-08-04 07:21:19",
"source": "https://www.travel-advisory.info/afghanistan"
}
},
"AG": {
"iso_alpha2": "AG",
"name": "Antigua and Barbuda",
"continent": "NA",
"advisory": {
"score": 3,
"sources_active": 3,
"message": "",
"updated": "2020-08-04 07:21:19",
"source": "https://www.travel-advisory.info/antigua-and-barbuda"
}
},
"AI": {
"iso_alpha2": "AI",
"name": "Anguilla",
"continent": "NA",
"advisory": {
"score": 3,
"sources_active": 3,
"message": "",
"updated": "2020-08-04 07:21:19",
"source": "https://www.travel-advisory.info/anguilla"
}
}
}我的问题是如何过滤continent : "AS"？P
回答 3
Stack Overflow用户
发布于 2020-08-05 00:05:06
$data = json_decode($response, true)['data'];
print_r($this->continentFilter($data, 'AS'));函数将如下所示：
private function continentFilter(array $data, string $continent): array
{
$filteredArray = [];
foreach ($data as $item) {
if ($item['continent'] === $continent) {
$filteredArray = $item;
break;
}
}
return $filteredArray;
}Stack Overflow用户
发布于 2020-08-05 00:02:23
如果大陆值与"AS“匹配，您可以遍历每个对象并推送到一个新数组。
使用$key => $value可以保留索引。
示例：
$filtered = [];
foreach ( $data->data as $key => $value )
{
if ( $value->continent === "AS" )
{
$filtered[$key] = $value;
}
}
print_r($filtered);将为您提供：
[AE] => stdClass Object
(
[iso_alpha2] => AE
[name] => United Arab Emirates
[continent] => AS
[advisory] => stdClass Object
(
[score] => 3.1
[sources_active] => 7
[message] =>
[updated] => 2020-08-04 07:21:19
[source] => https://www.travel-advisory.info/united-arab-emirates
)
)
[AF] => stdClass Object
(
[iso_alpha2] => AF
[name] => Afghanistan
[continent] => AS
[advisory] => stdClass Object
(
[score] => 5
[sources_active] => 10
[message] =>
[updated] => 2020-08-04 07:21:19
[source] => https://www.travel-advisory.info/afghanistan
)
)
...Stack Overflow用户
发布于 2020-08-05 00:05:00
您可以使用带有数组标志和array_filter方法的json_decode，如下所示：
$data = (json_decode($response, true))['data'];
$as = array_filter($data, function($item) {
return $item['continent'] === 'AS';
});还请注意，上面给出的json需要用大括号括起来，如下所示：
{
"data": {
...
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/63250278
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