我已经设计了一个代码,红色字体动词短语,并输出为HTML。
from __future__ import unicode_literals
import spacy,en_core_web_sm
import textacy
import codecs
nlp = en_core_web_sm.load()
sentence = 'The author is writing a new book. The dog is barking.'
pattern = r'<VERB>?<ADV>*<VERB>+'
doc = textacy.Doc(sentence, lang='en_core_web_sm')
lists = textacy.extract.pos_regex_matches(doc, pattern)
with open("my.html","w") as fp:
for list in lists:
search_word = (list.text)
fp.write(sentence.replace(search_word, '<span style="color: red">{}</span>'.format(search_word)))电流输出
The author **is writing** a new book. The dog is barking.The author is writing a new book. The dog **is barking.**句子被重复了两次,第一个是书写,最后一个是叫声被检测到。
预期输出:
The author **is writing** a new book. The dog **is barking.**在发送给列表检查之前,我应该做一个句子标记化吗?请帮帮忙?
发布于 2018-08-28 19:45:19
找到了另一种更符合逻辑的方法。与其在整个句子中进行替换,不如在具有该模式的句子中进行替换。
with open("my.html","w") as fp:
for _list in lists:
search_word = (_list.text)
containing_sentence = [i for i in sentence.split('.') if str(search_word) in str(i)][0]
fp.write(containing_sentence.replace(search_word, '<span style="color: red">{}</span>'.format(search_word)))上面的代码将分别编写句子。如果你想把它写成一个句子,在写到一个文件之前,将修改附加到一个列表中,并将它们连接起来,如下所示。
mod_sentence = []
for _list in lists:
search_word = (_list.text)
containing_sentence = [i for i in sentence.split('.') if str(search_word) in str(i)][0]+'.'
mod_sentence.append(containing_sentence.replace(search_word, '<span style="color: red">{}</span>'.format(search_word)))
with open("my.html","w") as fp:
fp.write(''.join(mod_sentence))希望这能有所帮助!干杯!
https://stackoverflow.com/questions/52048905
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