我在Java中为野生tic tac toe的一个变体实现了minimax算法,我偶然发现了一个问题。我有一个包含游戏网格的Node类、一个作为其子对象的Node对象的ArrayList,以及一个递归实现算法的minimax方法。
我得到的错误是:
Exception in thread "main" java.lang.OutOfMemoryError: GC overhead limit exceeded
at Grid.<init>(Grid.java:35)
at MiniMax$Node.findChildren(MiniMax.java:27)
at MiniMax.minimax(MiniMax.java:135)
at MiniMax.minimax(MiniMax.java:126)
at MiniMax.minimax(MiniMax.java:139)
at MiniMax.minimax(MiniMax.java:126)
at MiniMax.minimax(MiniMax.java:139)
at MiniMax.minimax(MiniMax.java:126)
at MiniMax.minimax(MiniMax.java:139)
at MiniMax.nextMove(MiniMax.java:77)
at ComputerPlayer.play(ComputerPlayer.java:12)
at TicTacToe.main(TicTacToe.java:146)
Process finished with exit code 1我认为问题的出现是因为子节点数量太多(总节点数: 2^8 * 8!)每次都会递归创建并存储到ArrayLists中。
下面是Node类:
private static class Node
{
protected Grid grid;
protected ArrayList<Node> children;
public Node(Grid grid)
{
this.grid = grid;
children = new ArrayList<>();
}
//Find all possible next moves
public void findChildren()
{
char[][] board = grid.getGrid();
for(int i = 0; i < board.length; i++)
{
for(int j = 0; j < board.length; j++)
{
if(board[i][j] == ' ')
{
board[i][j] = 'X';
children.add(new Node(new Grid(board)));
board[i][j] = 'O';
children.add( new Node(new Grid(board)));
board[i][j] = ' ';
}
}
}
}
}下面是minimax的实现:
private int minimax(Node state, int depth, boolean isMaximizer)
{
//If the game is in a terminal state or has reached the desired depth
boolean someoneWon = state.grid.someoneHasWon();
boolean isDraw = state.grid.isDraw();
if(someoneWon || isDraw || depth == 3)
{
return evaluateState(someoneWon, isDraw, !isMaximizer);//Evaluate the state
}
//MAX player's turn
if(isMaximizer)
{
//Find maximum score of all possible state's scores
int bestScore = Integer.MIN_VALUE;
state.findChildren();
for(int i = 0; i < state.children.size(); i++)
{
Node child = state.children.get(i);
int score = minimax(child, depth + 1, false);
bestScore = Math.max(bestScore, score);
}
return bestScore;
}
else//MIN player's turn
{
//Find minimum score of all possible move's scores
int bestScore = Integer.MAX_VALUE;
state.findChildren();
for(int i = 0; i < state.children.size(); i++)
{
Node child = state.children.get(i);
int score = minimax(child, depth + 1, true);
bestScore = Math.min(bestScore, score);
}
return bestScore;
}
}发布于 2020-04-03 05:29:24
不是创建子节点列表,而是将迭代移动到Node (或等效项。你会注意到,你不需要每次都创建一个新的板子-只需替换你在完成后改变的状态。
https://stackoverflow.com/questions/61001409
复制相似问题