首页
学习
活动
专区
圈层
工具
发布
    • 综合排序
    • 最热优先
    • 最新优先
    时间不限
  • 来自专栏blog(为什么会重名,真的醉了)

    Unity 3D项目-Adventure of JM Robot

    部分截图 演示 ---- Unity 3D项目-Adventure of JM Robot演示 (插播反爬信息 )博主CSDN地址:https://wzlodq.blog.csdn.net

    48310编辑于 2022-02-23
  • 来自专栏用户3288143的专栏

    【数据分析与可视化】DataFrame的Selecting和indexing

    1.78 33000 1 Color Gore Verbinski 302.0 169.0 563.0 1000.0 Orlando Bloom 40000.0 309404152.0 Action|Adventure 5000.0 7.1 2.35 0 2 Color Sam Mendes 602.0 148.0 0.0 161.0 Rory Kinnear 11000.0 200074175.0 Action|Adventure 1.78 33000 1 Color Gore Verbinski 302.0 169.0 563.0 1000.0 Orlando Bloom 40000.0 309404152.0 Action|Adventure 5000.0 7.1 2.35 0 2 Color Sam Mendes 602.0 148.0 0.0 161.0 Rory Kinnear 11000.0 200074175.0 Action|Adventure 1.78 33000 1 Color Gore Verbinski 302.0 169.0 563.0 1000.0 Orlando Bloom 40000.0 309404152.0 Action|Adventure

    53110发布于 2020-07-07
  • 来自专栏云计算linux

    微软数据库之微软自带数据库分析

    在 2000 年,Adventure Works Cycles 购买了位于墨西哥的小型生产厂 Importadores Neptuno。 Importadores Neptuno 为 Adventure Works Cycles 产品生产多种关键子组件。这些子组件将被运送到伯瑟尔市进行最后的产品装配。 Peter Greb,Adventure Works的IT顾问,决定实现Sql Server 2005以维护这个数据库。 数据库分析组研究了Adventure Works的每个部门使用的信息并且为名为Adventure Works的数据库创建了一个设计。 架构 ​ ​包含相关对象 ​ ​示例 ​ HumanResources Adventure Works Cycles 的雇员。

    64310编辑于 2024-12-17
  • 来自专栏FreeBuf

    PwnAdventure3:一款专为黑客而开发易受攻击的MMORPG游戏

    Pwn Adventure 3是一款专为黑客而开发的,易受攻击的第一人称MMORPG游戏,其目的旨在提升游戏开发人员的安全编码能力。 Pwn Adventure 3的游戏场景设置在一座美丽的岛屿上,在这个岛上任何情况都有可能发生,例如飞行,无限游戏虚拟币等。 使用Docker创建私人服务器 - Pwn Adventure 3:part 2 信息收集/侦察 - Pwn Adventure 3:part 3 使用gdb恢复游戏类 - Pwn Adventure 3:part 4 使用LD_PRELOAD Hooking Linux - Pwn Adventure 3:part 5 飞行以及我们的第一个flag! - 大冒险3:part 6 远程跳转和悬停(难以承受的复仇) - Pwn Adventure 3:part 7 找到隐藏的金蛋 - Pwn Adventure 3:part 8 开发一个TCP网络代理

    1.8K30发布于 2018-07-31
  • 来自专栏学习有记

    深入非聚集索引:SQL Server索引进阶 Level 2

    James isabella6@adventure-works.com 1015 David R Campbell david8@adventure-works.com Schmidt steve3@adventure-works.com 1743 Shannon C Guo shannon16@adventure-works.com Dockter blaine1@adventure-works.com 833 Clarence R. Tatman clarence0@adventure-works.com 1834 Heather M Wu heather6@adventure-works.com Maxham jennifer1@adventure-works.com 1561 Ido Ben-Sacha ido1@adventure-works.com

    2.2K30发布于 2018-07-19
  • 来自专栏算法channel

    数据处理的 3 个小技巧,都很实用

    Votes Revenue (Millions) Metascore 0 1 Guardians of the Galaxy Action,Adventure,Sci-Fi ... 757074 Revenue (Millions) Metascore 0 1 Action,Adventure,Sci-Fi ... 333.13 76.0 [1 rows 频次统计 下面统计电影 Genre 的频次, >>> vc = df["Genre"].value_counts() 下面显示电影 Genre 的 Top5 ,最高频为出现 50 次的 Action,Adventure ,Sci-Fi 类,次之为 48 次的 Drama 类: >>> vc.head() Action,Adventure,Sci-Fi 50 Drama 48

    70420发布于 2020-05-08
  • 来自专栏前端笔记薄

    MeiliSearch轻量级搜索引擎-食用指南

    '] }, { id: 3, title: 'Life of Pi', genres: ['Adventure', 'Drama'] }, { id: 4, title: 'Mad Max: Fury Road', genres: ['Adventure', 'Science Fiction'] }, { id: 5, title: 'Moana', genres: ['Fantasy', 'Action 的项 const search = await index.search( 'Adventure', { filter: ['id > 3'] } ) console.log(search) '] }, { id: 3, title: 'Life of Pi', genres: ['Adventure', 'Drama'] }, { id: 4, title: 'Mad Max: Fury Road', genres: ['Adventure', 'Science Fiction'] }, { id: 5, title: 'Moana', genres: ['Fantasy', 'Action

    4.2K20编辑于 2022-12-27
  • 来自专栏centosDai

    CA1055:URI 返回值不应是字符串

    public string GetReferrerUri(string httpHeader) { return "http://www.adventure-works.com" uriType) { } public Uri GetReferrerUri(string httpHeader) { return new Uri("http://www.adventure-works.com Function GetRefererUri(httpHeader As String) As String Return "http://www.adventure-works.com Function GetRefererUri(httpHeader As String) As Uri Return New Uri("http://www.adventure-works.com

    3400编辑于 2022-02-22
  • 来自专栏centosDai

    CA1054:URI 参数不应为字符串

    public string GetRefererUri(string httpHeader) { return "http://www.adventure-works.com"; uriType) { } public Uri GetRefererUri(string httpHeader) { return new Uri("http://www.adventure-works.com Function GetRefererUri(httpHeader As String) As String Return "http://www.adventure-works.com Function GetRefererUri(httpHeader As String) As Uri Return New Uri("http://www.adventure-works.com

    2800编辑于 2022-02-22
  • 来自专栏centosDai

    CA1054:URI 参数不应为字符串

    public string GetRefererUri(string httpHeader) { return "http://www.adventure-works.com"; uriType) { } public Uri GetRefererUri(string httpHeader) { return new Uri("http://www.adventure-works.com Function GetRefererUri(httpHeader As String) As String Return "http://www.adventure-works.com Function GetRefererUri(httpHeader As String) As Uri Return New Uri("http://www.adventure-works.com

    82620编辑于 2022-01-10
  • 来自专栏centosDai

    CA1056:URI 属性不应是字符串

    public string GetRefererUri(string httpHeader) { return "http://www.adventure-works.com"; uriType) { } public Uri GetRefererUri(string httpHeader) { return new Uri("http://www.adventure-works.com Function GetRefererUri(httpHeader As String) As String Return "http://www.adventure-works.com Function GetRefererUri(httpHeader As String) As Uri Return New Uri("http://www.adventure-works.com

    8050编辑于 2022-01-10
  • 来自专栏centosDai

    CA1055:URI 返回值不应是字符串

    public string GetReferrerUri(string httpHeader) { return "http://www.adventure-works.com" uriType) { } public Uri GetReferrerUri(string httpHeader) { return new Uri("http://www.adventure-works.com Function GetRefererUri(httpHeader As String) As String Return "http://www.adventure-works.com Function GetRefererUri(httpHeader As String) As Uri Return New Uri("http://www.adventure-works.com

    76020编辑于 2022-01-10
  • 来自专栏centosDai

    CA1056:URI 属性不应是字符串

    public string GetRefererUri(string httpHeader) { return "http://www.adventure-works.com"; uriType) { } public Uri GetRefererUri(string httpHeader) { return new Uri("http://www.adventure-works.com Function GetRefererUri(httpHeader As String) As String Return "http://www.adventure-works.com Function GetRefererUri(httpHeader As String) As Uri Return New Uri("http://www.adventure-works.com

    74920编辑于 2022-02-22
  • 来自专栏张善友的专栏

    SQL SERVER 2008 Hierarchyid数据类型

    HumanResources.EmployeeDemo (OrgNode, EmployeeID, LoginID, Title, HireDate) LUES (hierarchyid::GetRoot(), 1,'adventure-works , EmployeeID, LoginID, Title, HireDate) LUES (@Manager.GetDescendant(@FirstChild,NULL), 3, 'adventure-works , EmployeeID, LoginID, Title, HireDate) LUES (@Manager.GetDescendant(@FirstChild, NULL),55, 'adventure-works OrgNode, EmployeeID, LoginID, Title, HireDate) LUES (@Manager.GetDescendant(@FirstChild, NULL),531, 'adventure-works EmployeeID, LoginID, Title, HireDate) LUES (@Manager.GetDescendant(@FirstChild, @SecondChild),543, 'adventure-works

    1.6K100发布于 2018-01-19
  • 来自专栏Soul Joy Hub

    pyspark 特征工程

    genres| +-------+--------------------+--------------------+ | 1| Toy Story (1995)|Adventure |Animati...| | 2| Jumanji (1995)|Adventure|Childre...| | 3|Grumpier Old Men ...| ----------------+--------------------+-------------+----------------+ | 1| Toy Story (1995)|Adventure |Animati...| 1|(1001,[1],[1.0])| | 2| Jumanji (1995)|Adventure|Childre...| |movieId| title| genre| +-------+----------------+---------+ | 1|Toy Story (1995)|Adventure

    2.4K10发布于 2021-03-20
  • 来自专栏算法channel

    2 个数据处理的小功能,非常实用!

    1000 行数据,genre 取值的频次统计如下: vc = df["genre"].value_counts() vc 打印结果: Action,Adventure,Sci-Fi 50 Adventure,Comedy,Fantasy 1 Biography,History,Thriller 1 Action,Horror 1 Mystery 207, dtype: int64 筛选出 top3 的 index: top_genre = vc[0:3].index print(top_genre) 打印结果: Index(['Action,Adventure

    45440发布于 2020-05-08
  • Go 类型系统技巧:Go 高手和新手的分水岭:会不会把 int 包一层 type UserID int

    const(Adventure="Adventure"Mystery="Mystery"Magic="Magic")你开心地写:展开代码语言:GoAI代码解释book:=Book{ID:42,Name: 省空间,但更“反人类”于是你改用数字:展开代码语言:GoAI代码解释const(Adventure=1Mystery=2Magic=3)typeBookstruct{Genreint//省了90%内存! 展开代码语言:GoAI代码解释func(gGenre)String()string{switchg{caseAdventure:return"Adventure"caseMystery:return"Mystery"caseMagic 加个ParseGenre:展开代码语言:GoAI代码解释vargenreMap=map[string]Genre{"Adventure":Adventure,"Mystery":Mystery,"Magic

    18310编辑于 2025-12-22
  • 来自专栏开源技术小栈

    实时通信 | 轻量级搜索引擎MeiliSearch

    'genres' => ['Romance, Drama']], ['id' => 2, 'title' => 'Wonder Woman', 'genres' => ['Action, Adventure ']], ['id' => 3, 'title' => 'Life of Pi', 'genres' => ['Adventure, Drama']], ['id' => 4, 'title ' => 'Mad Max: Fury Road', 'genres' => ['Adventure, Science Fiction']], ['id' => 5, 'title' => '

    3.1K20编辑于 2023-03-08
  • 来自专栏linux运维

    编程冒险:用 Flask 打造你的待办事项 Web 应用,闯关“任务大师”!

    第一关:搭建冒险基地创建项目目录:新建一个文件夹 todo-adventure,作为你的冒险基地。 初始化环境:打开终端,进入 todo-adventure,运行以下命令安装 Flask:pip install flask创建主文件:在 todo-adventure 里建个 app.py 文件,输入以下代码 创建模板文件夹:在 todo-adventure 里建个 templates 文件夹,Flask 会从这里找 HTML 文件。

    25221编辑于 2025-07-20
  • 来自专栏拭心的安卓进阶之路

    策略模式:网络小说的固定套路

    /** * 穷困潦倒的开始 */ void badStart(); /** * 突然有天遇到神人/捡到神器,实力大涨 */ void adventure ; } @Override public void adventure() { System.out.println(mName + " 因为意外来到恶魔岛,在恶魔岛上遇见了恶魔的仆人 ; } @Override public void getContent() { badStart(); adventure(); ; } @Override public void adventure() { System.out.println(mName + " 在一次伐竹过程中,为追一只三眼灵猴 ; } @Override public void getContent() { badStart(); adventure();

    54830编辑于 2022-05-10
领券