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  • 来自专栏饶文津的专栏

    【2016 ACMICPC Asia Regional Qingdao Online】

    而且,不超过1e9的乘积不过5000多个,于是预处理出来,然后每次二分找就可以了。

    98610发布于 2020-06-02
  • 来自专栏Java架构师必看

    2012 ACMICPC Asia Regional Changchun Online-LianLianKan

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2389    Accepted Submission(s): 382

    42720发布于 2021-05-14
  • 来自专栏小L的魔法馆

    Problem 1004-2017 ACMICPC Asia Regional Shenyang Online

    题目来源:array array array Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 0 Accepted Submission(s): 0 题目描述和输出: One day, Kaitou Kiddo had stolen a priceless diamond ring. But detective Conan bl

    53630发布于 2019-02-21
  • 来自专栏Java架构师必看

    2012 ACMICPC Asia Regional Tianjin Online-Faulty Odometer

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1027    Accepted Submission(s): 681

    32950发布于 2021-05-14
  • 来自专栏小L的魔法馆

    Problem 1002-2017 ACMICPC Asia Regional Shenyang Online

    网络赛:2017 ACM/ICPC Asia Regional Shenyang Online 题目来源:cable cable cable Problem Description: Connecting

    43310发布于 2019-02-21
  • 来自专栏机器学习、深度学习

    人体姿态估计--RMPE: Regional Multi-Person Pose Estimation

    RMPE: Regional Multi-Person Pose Estimation ICCV2017 Code is based Caffe and Torch! SPPE 对每个矩形框都会产生一个姿态,所以重复检测导致了冗余姿态 为了解决上述两个问题, 我们提出一个 regional multi-person pose estimation (RMPE) framework 3 Regional Multi-person Pose Estimation 首先用人体检测器得到 human bounding boxes, 可以用 SSD 或 Faster R-CNN。

    1.7K10发布于 2019-05-26
  • 来自专栏CSDN旧文

    2019-2020 ICPC, Asia Jakarta Regional Contest A. Copying Homework (思维)

    Danang and Darto are classmates. They are given homework to create a permutation of N integers from 1 to N. Danang has completed the homework and created a permutation A of N integers. Darto wants to copy Danang's homework, but Danang asks Darto to change it up a bit so it does not look obvious that Darto copied.

    53910发布于 2020-10-28
  • 来自专栏Zaqdt_ACM

    The 2018 ACM-ICPC Asia Qingdao Regional Contest J. Books(思维)

    题目链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=4067        题意是有n本书,然后一个人很有钱,他要买m本

    54910发布于 2019-01-10
  • 来自专栏wym

    The 2018 ACM-ICPC Asia Qingdao Regional Contest, Online(四题签到)

    C题 用map超时,mmp map一直超时写了两个小时,单纯的数组就行 思路:有n条指令,值为r 存下执行第i条指令的时候的值r,若重复则输出“No” 否则“Yes”  //C #include <stdio.h> #include <string.h> #include <stdlib.h> #include <math.h> #include <algorithm> using namespace std; typedef long long llong; const int MAXN = 10000

    66620发布于 2018-09-29
  • 来自专栏ypw

    ICPC Pacific Northwest Regional Contest 2019 C D E M 题解

    D 标准签到,因为只能加跟除,所以 A =< B 时就只能执行加法操作 然后 A > B 时,只能对A 不是偶数变偶数然后除 就这样子一直到 A < B。然后执行加法操作。

    55110发布于 2020-09-10
  • 来自专栏CSDN旧文

    2019-2020 ICPC, Asia Jakarta Regional Contest C. Even Path(思维)

    Pathfinding is a task of finding a route between two points. It often appears in many problems. For example, in a GPS navigation software where a driver can query for a suggested route, or in a robot motion planning where it should find a valid sequence of movements to do some tasks, or in a simple maze solver where it should find a valid path from one point to another point. This problem is related to solving a maze.

    49510发布于 2020-10-28
  • 来自专栏Zaqdt_ACM

    The 2018 ACM-ICPC Asia Qingdao Regional Contest M. Function and Function(规律)

    题目链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=4070        题意是输入一个数n,然后我们要求这个数的每一

    50820发布于 2019-01-10
  • 来自专栏ACM小冰成长之路

    HDU-2017 ACMICPC Asia Regional Qingdao Online-1009-Smallest Minimum Cut

    该文是介绍一种计算最大流的方法,主要是利用Dinic算法,并且使用动态规划来避免重复计算。该方法应用于计算最大流问题,例如交通网络中的车辆路径规划。

    70580发布于 2018-01-09
  • 来自专栏owent

    The 35th ACMICPC Asia Regional Tianjin Site —— Online Contest 1009 Convex 解题报告

    The 35th ACM/ICPC Asia Regional Tianjin Site —— Online Contest 2010年天津赛 网络赛 I题 Convex 题目链接:http://acm.hdu.edu.cn

    39620编辑于 2023-03-05
  • 来自专栏ACM小冰成长之路

    HDU-2017 ACMICPC Asia Regional Qingdao Online-1011-A Cubic number and A Cubic Number

    该文章介绍了如何通过枚举法求解一个三次方程,该方程具有形式 ax^3 + bx^2 + cx + d = 0,并给出了相应的代码实现。

    70770发布于 2018-01-09
  • 来自专栏ACM小冰成长之路

    HDU-2017 ACMICPC Asia Regional Qingdao Online-1008-Chinese Zodiac

    该文介绍了如何计算两个字符串之间的最长公共子序列长度,并给出了具体的实现代码。同时,还介绍了如何根据输入的字符串计算出对应的最长公共子序列长度,并输出结果。

    61970发布于 2018-01-09
  • 来自专栏一Wa哇一天

    2019-2020 ICPC Southeastern European Regional Programming Contest (SEERC 2019)-G.Projection

    Everybody knows that you are a TensorFlow fan. Therefore, you’ve been challenged to recreate the TensorFlow logo from two projections.

    1.2K20发布于 2020-04-09
  • 来自专栏CSDN旧文

    数学--数论--HDU--5878 Count Two Three 2016 ACMICPC Asia Regional Qingdao Online 1001

    这个题的意思是让你找到一个k大于n并且能写成 2 a 3 b 5 c 7 d 2^a3^b5^c7^d 2a3b5c7d这种形式。 然后就先把能写成这种形式的数的全部处理出来,在进行二分查找,比这个大的最小的数。

    38350发布于 2020-10-28
  • 来自专栏机器学习、深度学习

    无人机数车--Drone-based Object Counting by Spatially Regularized Regional Proposal Network

    Drone-based Object Counting by Spatially Regularized Regional Proposal Network ICCV2017 数据库:https

    1.1K100发布于 2018-01-03
  • 来自专栏sukuna的博客

    Online Selection Contest BACS Regional Programming Contest, 2018 And BACS High School Programming Co

    Online Selection Contest BACS Regional Programming Contest, 2018 And BACS High School Programming Contest

    35210编辑于 2022-12-08
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