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- 来自专栏Phoenix的Android之旅
Android基础操作-文件解压缩
关键类 可以归纳起来所有跟文件操作相关的流程都要下面这几个类 File InputStream OutputStream 解压缩也一样，用于解压缩的工具类是这三个， ZipFile ZipInputStream FileOutputStream 解压缩流程 首先实例化ZipFile对象， 通过InputStream读取流，ZipInputStream提供了一个方法 getNextEntry() 返回一个 ZipEntry return; } ZipFile zipFile = new ZipFile(file); ZipInputStream zipInputStream = new ZipInputStream(new FileInputStream(file)); ZipEntry zipEntry = null ; while ((zipEntry = zipInputStream.getNextEntry()) !
2.8K40发布于 2018-08-07 - 来自专栏分享学习
【SpringBoot项目实践】图片压缩包处理、遍历上传至文件服务器
假设的文件服务器客户端 public void processAndUploadImages(MultipartFile file) throws IOException { ZipInputStream zipInputStream = new ZipInputStream(file.getInputStream()); ZipEntry entry; while (( entry = zipInputStream.getNextEntry()) ! fileServerClient.uploadFile(entry.getName(), imgBytes); } } zipInputStream.closeEntry (); } zipInputStream.close(); } } 编写文件服务器客户端 根据所选择的文件服务器（如FastDFS、MinIO），实现对应的文件服务器客户端类
63510编辑于 2025-05-18 - 来自专栏明明如月的技术专栏
Java 解压缩 Zip文件（在李兴华老师基础上优化）
java.io.OutputStream; import java.util.zip.ZipEntry; import java.util.zip.ZipFile; import java.util.zip.ZipInputStream SWT_Designer.zip");//要解压的文件 File outFile = null; ZipFile zipFile = new ZipFile(file);//创建压缩文件对象 ZipInputStream InputStream is = null; OutputStream os = null; ZipEntry entry = null ; // 每一个压缩实体 zi = new ZipInputStream (new FileInputStream(file));// 实例化ZIpInputStream String dir = file.getName().substring(0, file.getName
75420发布于 2021-08-27 - 来自专栏小小码农一个。
获取压缩包中的文本字符串。
//获取ZIP输入流(一定要指定字符集Charset.forName("GBK")否则会报java.lang.IllegalArgumentException: MALFORMED) ZipInputStream zipInputStream = new ZipInputStream(new BufferedInputStream(input), Charset.forName("GBK")); //定义ZipEntry置为null,避免由于重复调用zipInputStream.getNextEntry造成的不必要的问题 ZipEntry ze = null; / String publicKey = ""; //密文 String cipher = ""; //循环遍历 while ((ze = zipInputStream.getNextEntry = null) { //读取 BufferedReader br = new BufferedReader(new InputStreamReader(zipInputStream
2.4K20发布于 2020-06-08 - 来自专栏Java升级打怪进阶之路
Java把文件压缩成.zip压缩包和解压.zip压缩包(ZipOutputStream、ZipInputStream)
path_to_dest) throws IOException { try (FileInputStream fis = new FileInputStream(fileZip); ZipInputStream zis = new ZipInputStream(new BufferedInputStream(fis))) { ZipEntry entry; // 从ZipInputStream读取每个条目，直到没有 // 发现更多条目，返回值为空 // getNextEntry()方法。
1.8K20编辑于 2022-11-28 - 来自专栏java开发的那点事
Activiti7 zip部署,查询及其删除
org.activiti.engine.repository.Deployment; import java.io.IOException; import java.io.InputStream; import java.util.zip.ZipInputStream resourceAsStream = ActivitiZipDeployment.class.getClassLoader().getResourceAsStream("pic.zip"); ZipInputStream zipInputStream = new ZipInputStream(resourceAsStream); Deployment deploy = repositoryService.createDeployment ().addZipInputStream(zipInputStream).name("请假申请流程").deploy(); zipInputStream.close();
63211发布于 2020-12-01 - 来自专栏星河造梦坊专栏
Unity网络交互☀️压缩包zip下载与解压
= Encoding.GetEncoding("gbk"); ZipConstants.DefaultCodePage = gbk.CodePage; using (ZipInputStream zipInputStream = new ZipInputStream(_inputStream)) { if (! string.IsNullOrEmpty(_password)) zipInputStream.Password = _password; while = (entry = zipInputStream.GetNextEntry())) { if (null == entry || string.IsNullOrEmpty ZipByte, string password = null) { bool result = true; FileStream fs = null; ZipInputStream
68410编辑于 2024-08-15 - 来自专栏好好学习，天天向上
Java中zip的压缩和解压缩
在Java中可以使用ZipOutputStream和ZipInputStream来实现zip的压缩和解压缩操作，另外使用FileSystem也可以用来实现zip的解压缩，下面将介绍这几种方式，直接上代码 @Test public void testDecompressByZip() { try ( //指定需要解压缩的zip文件 ZipInputStream zipInputStream = new ZipInputStream(new FileInputStream("F:\\myFavorites.zip")) ) { ZipEntry zipEntry; byte[] byteArray ; int len; //遍历zip文件中的所有项，并逐个解压到指定的目录中 while ((zipEntry = zipInputStream.getNextEntry()) ! FileOutputStream("F:\\我的解压目录\\" + zipEntry.getName())) { byteArray = new byte[1024]; while ((len = zipInputStream.read
3.4K20发布于 2021-03-04 - 来自专栏繁依Fanyi 的专栏
【Java 基础篇】Java Zip压缩：简化文件和文件夹的压缩操作
zipInputStream = new ZipInputStream(new FileInputStream(zipFileName))) { // 解压缩文件 unzipFiles(zipInputStream, outputFolder); System.out.println("Files unzipped zipInputStream, String outputFolder) throws IOException { byte[] buffer = new byte[1024]; ZipEntry entry; while ((entry = zipInputStream.getNextEntry()) ! (); } } } 在上面的示例中，我们首先创建一个ZipInputStream对象，并传入一个FileInputStream来读取Zip文件。
8.3K41编辑于 2023-10-12 - 来自专栏.NET 全栈开发专栏
ICSharpCode.SharpZipLib.Zip 解析时报错System.NotSupportedException: No data is availa
分析原因利用ICSharpCode.SharpZipLib.Zip进行APK解析时，因为APK内编译的名称为中文，查询微软开发文档936为gb2312中文编码微软开发文档地址// 错误代码using (ZipInputStream zip = new ZipInputStream(File.OpenRead(path))) {using (var filestream = new FileStream(path, FileMode.Open BinaryReader s = new BinaryReader(strm)) {resourcesData = s.ReadBytes((int)entry.Size);}}}}}}// 解决方法using (ZipInputStream zip = new ZipInputStream(File.OpenRead(path))) {using (var filestream = new FileStream(path, FileMode.Open
52540编辑于 2023-10-31 - 来自专栏Android干货
项目实战工具类（二）：ZipUtils(压缩/解压缩文件相关)
import java.util.List; import java.util.zip.ZipEntry; import java.util.zip.ZipFile; import java.util.zip.ZipInputStream UnZipFolder(String zipFileString, String outPathString , Context context) throws Exception { ZipInputStream inZip = new ZipInputStream(new FileInputStream(zipFileString)); ZipEntry zipEntry; inZip = new ZipInputStream(new FileInputStream(zipFileString)); ZipEntry zipEntry; while inZip = new ZipInputStream(new FileInputStream(zipFileString)); ZipEntry zipEntry; String
2.5K20发布于 2018-12-14 - 来自专栏棒棒小飞人
工具类ZipUtils.java代码
.*; import java.util.UUID; import java.util.zip.ZipEntry; import java.util.zip.ZipInputStream; import unZipFile.exists()) { unZipFile.mkdirs(); } //ZipInputStream用来读取压缩文件的输入流 ZipInputStream zipInputStream = new ZipInputStream(multipartFile.getInputStream()); / 可以是文件，也可以是路径，比如abc/test/路径下 ZipEntry zipEntry; try { while ((zipEntry = zipInputStream.getNextEntry (); } zipInputStream.close(); fileHandleResponse.setSuccess(1);
99400发布于 2021-10-07 - 来自专栏Java学习网
项目实践工作流之Activiti学习（十九）
InputStream inputStream = this .getClass() .getClassLoader() .getResourceAsStream( " diagram/holiday.zip"); ZipInputStream zipInputStream = new ZipInputStream(inputStream); // 获取repositoryService RepositoryService repositoryService getRepositoryService(); // 流程部署 Deployment deployment = repositoryService.createDeployment()// .addZipInputStream(zipInputStream
30830编辑于 2023-11-01 - 来自专栏.NET 全栈开发专栏
利用ICSharpCode.SharpZipLib.dll解析 出错：“Wrong Local header signature: 0xFF8”
分析原因利用ICSharpCode.SharpZipLib.dll解析APK时，进入APK的AndroidXml获取时出现报错出错代码using (ICSharpCode.SharpZipLib.Zip.ZipInputStream zip = new ICSharpCode.SharpZipLib.Zip.ZipInputStream(File.OpenRead(path))) {using (var filestream = BinaryReader(strm)) {resourcesData = s.ReadBytes((int)s.BaseStream.Length);}}}}}解决方法经过查阅资料，解决方法如下using (ZipInputStream zip = new ZipInputStream(File.OpenRead(path))) {using (var filestream = new FileStream(path, FileMode.Open
79240编辑于 2023-10-31 - 来自专栏同步文章
activiti（二）流程实例
cn.panda.c_processInstance; import java.io.InputStream; import java.util.List; import java.util.zip.ZipInputStream InputStream in =this.getClass().getClassLoader().getResourceAsStream("diagrams/helloworld.zip"); ZipInputStream zipInputStream=new ZipInputStream(in); Deployment deployment = processEngine.getRepositoryService ()//创建部署对象 .name("流程定义")//添加部署对象 .addZipInputStream(zipInputStream
41530编辑于 2023-10-12 - 来自专栏项勇
笔记101 | 文件的压缩与解压笔记
system/etc/freq_logo.zip"); if(file.canRead() && file.isFile()) { try { // create a ZipInputStream instance ZipInputStream is = null; try { is = new ZipInputStream freq_logo.zip" ) ; // get a ZipFile instance ZipFile zipFile = new ZipFile ( file ) ; // create a ZipInputStream instance ZipInputStream zis = new ZipInputStream ( new FileInputStream ( file ) ) ;
54120发布于 2020-07-24 - 来自专栏Java学习网
如何使用Java进行文件压缩和解压缩
Java提供了ZipInputStream和GZIPInputStream类来完成文件解压缩的任务。 ZipInputStream类可以用于解压缩ZIP格式的文件，下面是一个演示程序： import java.io.*; import java.util.zip.*; public class UnZipExample { public static void main(String[] args) { byte[] buffer = new byte[1024]; try { ZipInputStream zis = new ZipInputStream(new FileInputStream("compressed.zip")); ZipEntry zipEntry = zis.getNextEntry } catch (IOException e) { e.printStackTrace(); } } } 上述代码中，我们首先定义一个名为“compressed.zip”的ZipInputStream
1.4K20编辑于 2023-12-15 - 来自专栏JAVA
如何使用Java进行文件压缩和解压缩
.*; import java.awt.image.BufferedImage; import javax.imageio.ImageIO; 文件解压缩示例： // 创建解压缩对象 ZipInputStream zipInputStream = new ZipInputStream(new FileInputStream("compressed.zip")); // 逐个解压缩条目 ZipEntry entry = zipInputStream.getNextEntry(); while (entry ! zipInputStream.closeEntry(); entry = zipInputStream.getNextEntry(); } zipInputStream.close(); 图片压缩示例
1.1K10编辑于 2024-11-20 - 来自专栏黑泽君的专栏
day57_BOS项目_09
import java.io.InputStream; import java.io.OutputStream; import java.util.List; import java.util.zip.ZipInputStream (); // 方式二：加载zip文件 // 从根路径下读一个文件，并返回该文件对应的输入流，使用类加载器对象获取classpath路径下的文件 // ZipInputStream zipInputStream = new ZipInputStream(this.getClass().getClassLoader().getResourceAsStream("process.zip ")); // 直接new一个文件输入流，文件位置灵活 ZipInputStream zipInputStream = new ZipInputStream(new FileInputStream "e:\\process.zip"))); // 将.png文件和.bpmn文件压缩到process.zip中 deploymentBuilder.addZipInputStream(zipInputStream
52020发布于 2018-10-18 - 来自专栏编码小白
activiti学习笔记(五) 流程部署
addBytes(String resourceName, byte[] bytes); //根据zip流进行部署 DeploymentBuilder addZipInputStream(ZipInputStream zipInputStream); //根据BpmnModel实例进行部署 DeploymentBuilder addBpmnModel(String resourceName, BpmnModel App.class.getClassLoader().getResourceAsStream( "com/activiti_study/ch10/common.zip"); ZipInputStream zipInputStream = new ZipInputStream(in); DeploymentBuilder deployment = repositoryService.createDeployment (); deployment.addZipInputStream(zipInputStream).deploy(); } 普通流部署 根据资源文件路径，获取其流，进行部署
2.9K70发布于 2018-03-08
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